摘要: 1.引用Windows.Form 2.打开文件 1 System.Windows.Forms.OpenFileDialog openFileDialog1 = new System.Windows.Forms.OpenFileDialog(); 2 openFileDialog1.InitialDi 阅读全文
posted @ 2020-11-05 11:55 木板 阅读(598) 评论(0) 推荐(0)