摘要: A. Forbidden Integer 模拟: void solve(){ int n,k,x; cin>>n>>k>>x; if(x!=1){ cout<<"YES\n"<<n<<"\n"; for(int i=1;i<=n;i++) cout<<"1"<<" \n"[i==n]; return 阅读全文
posted @ 2023-06-30 14:22 橘赴亦梦人ω 阅读(170) 评论(0) 推荐(0)