C# 科学计数法转换成数字

/// <summary>
/// 判断输入的数是否是科学计数法。如果是的话,就会将其换算成整数并且返回,否则就返回false。
/// </summary>
/// <param name="num"></param>
/// <param name="CompleteNum"></param>
/// <returns></returns>
private bool ChkNum(string num, ref decimal CompleteNum)
{
bool result = false;
bool resultSymbol = num.Contains("*");
bool result0 = num.Contains("^");
if ((resultSymbol == true) && (result0 == true))
{ //当数字中有*和^的时候,进行下面的判断
int IntSymbol = num.IndexOf("*");
int Symbol0 = num.IndexOf("^");
if (((Symbol0 - IntSymbol) == 3))
{//当*在^前面的时候
string numA = num.Substring(0, IntSymbol);//截取*号前面的数字(基数);
string numB = num.Substring(IntSymbol+1, Symbol0 - IntSymbol-1);//截取10;
string numC = num.Substring(Symbol0+1, num.Length - Symbol0-1);//获得幂次数
Regex regNum0 = new Regex(@"^(\-|\+)?\d+(\.\d+)?$");
Regex regNum2 = new Regex(@"^-[1-9]\d*$|^[1-9]\d*$");
if ((regNum0.IsMatch(numA)) && (numB == "10") && (regNum2.IsMatch(numC)))
{
decimal dcNumA;
decimal.TryParse(numA,out dcNumA);
decimal dcNumC;
decimal.TryParse(numC, out dcNumC);//将幂次数转换成decimal类型
decimal zhengshu = 10;
if (dcNumC > 0)
{//当幂次数为整数的时候
for (int i = 0; i < dcNumC - 1; i++)
{
zhengshu *= 10;
}
}
else
{//当幂次数为负数的时候
for (int i = 0; i < Math.Abs(dcNumC) + 1; i++)
{
zhengshu /= 10;
}
}
CompleteNum = dcNumA * zhengshu;
result = true;
}
else
{
result = false;
}
}
else
{
result = false;
}
}
else
{
result = false;
}
return result;
}

posted @ 2018-05-14 09:01  一念如是  阅读(5800)  评论(0编辑  收藏  举报