【Leetcode】Clone Graph

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.


OJ's undirected graph serialization:

Nodes are labeled uniquely.

We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.

 

As an example, consider the serialized graph {0,1,2#1,2#2,2}.

The graph has a total of three nodes, and therefore contains three parts as separated by #.

  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

 

Visually, the graph looks like the following:

       1
      / \
     /   \
    0 --- 2
         / \
         \_/
 1 /**
 2  * Definition for undirected graph.
 3  * struct UndirectedGraphNode {
 4  *     int label;
 5  *     vector<UndirectedGraphNode *> neighbors;
 6  *     UndirectedGraphNode(int x) : label(x) {};
 7  * };
 8  */
 9 class Solution {
10 public:
11     UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
12         unordered_map<UndirectedGraphNode *, UndirectedGraphNode *> map;
13         if (node == nullptr) {
14             return nullptr;
15         }
16         return clone(node, map);
17     }
18 private:
19     UndirectedGraphNode *clone(UndirectedGraphNode *node, 
20             unordered_map<UndirectedGraphNode *, UndirectedGraphNode *> &map) {
21         if (map.find(node) != map.end()) {
22             return map[node];
23         } 
24         UndirectedGraphNode *new_node = new UndirectedGraphNode(node->label);
25         map[node] = new_node;
26         for (auto n : node->neighbors) {
27             new_node->neighbors.push_back(clone(n, map));
28         }
29         return new_node;
30     }
31 };
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posted @ 2014-06-03 20:51  小菜刷题史  阅读(332)  评论(0编辑  收藏  举报