hdu 2544 (Dijkstra/SPFA模板)

 

/*
此题纯属套模板
调用时,初始结点s,目标结点e,则
SPFA(s);
cout<<d[e]<<endl;
即可。注意结点是从1存储到N。
不能连通时值为MAX*/
#include <stdio.h>
#include <string.h>

int d[1002],n,m;
int edges[1005][1005];
int queue[1000001];
#define MAX 999999999
#define N 1001
/*
int SPFA(int s)
{
    int i;
    bool visit[N] = {false};
    int front = 0, rear = 1; 
    memset(queue,0,sizeof(queue));
    for(i=1;i<=n;i++)
        d[i] = MAX;
    //int path[N];
    queue[front] = s;
    visit[s] = true;
    d[s] = 0;
    while(front<rear)
    {
        int u = queue[front];
        visit[u] = false;
        for(int i=1; i<=n; i++)
        {
            if (d[i]>d[u]+ edges[u][i])
            {
                d[i]= d[u]+edges[u][i];
                //path[i] = u;
                if( !visit[i] )
                {
                    visit[i] = true;
                    queue[rear++] = i;
                }
            }
        }
        front++;
    }
    return 0;
}
*/
void dijkstra(int v)
{
        int i,j;
        bool s[N]={false};
        for(i=1;i<=n;i++)
                d[i]=edges[v][i];
        d[v]=0;s[v]=true;
        for(i=1;i<n;i++)
        {
                int temp=MAX;
                int u=v;
                for(j=1;j<=n;j++)
                        if((!s[j])&&(d[j]<temp))
                        {
                                u=j;
                                temp=d[j];
                        }
                        s[u]=true;
                        for(j=1;j<=n;j++)
                                if((!s[j])&&(edges[u][j]<MAX)&&(d[u]+edges[u][j])<d[j])
                                        d[j]=d[u]+edges[u][j];
        }
  
}

int main()
{
    int i,j,a,b,c;
    while(scanf("%d%d",&n,&m)!=EOF&&(n||m))
    {
        for(i=0;i<=1000;i++){
            for(j=0;j<=i;j++)
            {
                edges[i][j]=MAX;
                edges[j][i]=MAX;
            }
        }
        for(i=0;i<m;i++)
        {
            scanf("%d %d %d",&a,&b,&c);
            if(edges[a][b]>c){
                edges[a][b]=c;
                edges[b][a]=c;
            }
        }
        
      //  SPFA(1);
		dijkstra(1);
        printf("%d\n",d[n]);
    }
    return 0;
}
posted @ 2010-11-20 22:27  kfinder  阅读(2153)  评论(0编辑  收藏  举报