Yan_Bin

2016年9月4日

摘要： 10892 LCM CardinalityA pair of numbers has a unique LCM but a single number can be the LCM of more than one possiblepairs. For example 12 is the LCM o 阅读全文

posted @ 2016-09-04 01:03 Yan_Bin 阅读(203) 评论(0) 推荐(0) 编辑

UVa10780

摘要： 10780 Again Prime? No time.The problem statement is very easy. Given a number n you have to determine the largest power of m,not necessarily prime, th 阅读全文

posted @ 2016-09-04 00:28 Yan_Bin 阅读(198) 评论(0) 推荐(0) 编辑

2016年9月3日

UVa10943

摘要： 10943 How do you add?Larry is very bad at math — he usually uses a calculator, which workedwell throughout college. Unforunately, he is now struck in 阅读全文

posted @ 2016-09-03 17:56 Yan_Bin 阅读(153) 评论(0) 推荐(0) 编辑

计算组合数

摘要：有两种计算方式，直接计算或者递推计算：阅读全文

posted @ 2016-09-03 17:16 Yan_Bin 阅读(157) 评论(0) 推荐(0) 编辑

UVa11889

摘要： 11889 BenefitRecently Yaghoub is playing a new trick to sell some more. When somebody gives him A Tomans, hewho never has appropriate changes, asks fo 阅读全文

posted @ 2016-09-03 16:16 Yan_Bin 阅读(226) 评论(0) 推荐(0) 编辑

UVa11388

摘要： 11388 GCD LCMThe GCD of two positive integers is the largest integer that divides both the integers without anyremainder. The LCM of two positive inte 阅读全文

posted @ 2016-09-03 11:40 Yan_Bin 阅读(182) 评论(0) 推荐(0) 编辑

2016年9月2日

二分查找

摘要：通过展示STL中已存在的lowerbound和uppebound函数来展示二分查找。阅读全文

posted @ 2016-09-02 20:04 Yan_Bin 阅读(125) 评论(0) 推荐(0) 编辑

UVa12096

摘要： 12096 The SetStack ComputerBackground from Wikipedia: \Set theory is a branch ofmathematics created principally by the German mathe-matician Georg Can 阅读全文

posted @ 2016-09-02 19:36 Yan_Bin 阅读(436) 评论(0) 推荐(0) 编辑

UVa156

摘要：题意：输入一些单词，找出所有满足以下条件的单词：该单词不能通过字母重排得到输入文本中的另外一个单词。在判断是否满足条件时，字母不区分大小写，但在输出时应该保留输入中的大小写，按字典序进行排列。分析：将输入的单词进行“标准化”，即将单词中的每个字母化为小写并按字典序重排单词，用一个字典来统计一个阅读全文

posted @ 2016-09-02 17:59 Yan_Bin 阅读(441) 评论(0) 推荐(0) 编辑

UVa400

摘要： 400 Unix lsThe computer company you work for is introducing a brand new computer line and is developing a newUnix-like operating system to be introduc 阅读全文

posted @ 2016-09-02 17:25 Yan_Bin 阅读(241) 评论(0) 推荐(0) 编辑

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