摘要：环境：access2003 + win7有图有真相：明显地看到，日期那里显示了“星期X”，问题的根源就在这里。。。更改计算机的日期显示设置为不显示星期~方法：点击右下角的时钟-点击“更改日期和时间设置”-点击“更改日期和时间”-点击“更改日历设置”-设置日期格式（我想最好根据数据库表中的日期格式更改吧）~然后就可以正常使用access啦~2013-09-2920:04:41 阅读全文

摘要：myLabel->setStyleSheet("border:1px solid black");简要说明：border就是边缘。px是像素，1px就是边框的宽度。solid是实线，边框设置为实线。black设置边框为黑色，还可以用green、red等。用rgb(para1 , para2, para3)也可控制颜色。2013-09-28 17:02:30 阅读全文

摘要：Guardian of DecencyTime Limit:3000MSMemory Limit:0KB64bit IO Format:%lld & %lluSubmitStatusPracticeUVALive 3415DescriptionProblem H - Guardian of DecencyTime limit: 15 secondsFrank N. Stein is a very conservative high-school teacher. He wants to take some of his students on an excursion, but he 阅读全文

摘要：背景：设G=(V,E)是一个无向图。如顶点集V可分区为两个互不相交的子集V1,V2之并，并且图中每条边依附的两个顶点都分属于这两个不同的子集。则称图G为二分图。二分图也可记为G=(V1,V2,E)。给定一个二分图G，在G的一个子图M中，M的边集{E}中的任意两条边都不依附于同一个顶点，则称M是一个匹配。 选择这样的子集中边数最大的子集称为图的最大匹配问题(maximal matching problem)（引自维基百科）1. 匹配边：连结分属于V1和V2的两个顶点的边。其他边是未匹配边。2.匹配点：匹配边所连结的顶点。不在匹配边上的顶点就是未匹配点。3.交错路：设P是图G的一条路，如果P的任意 阅读全文

摘要：Simple Moleculestime limit per test1 secondmemory limit per test256 megabytesinputstandard inputoutputstandard outputMad scientist Mike is busy carrying out experiments in chemistry. Today he will attempt to join three atoms into one molecule.A molecule consists of atoms, with some pairs of atoms co 阅读全文

摘要：Heavy TransportationTime Limit:3000MSMemory Limit:30000KB64bit IO Format:%I64d & %I64uSubmitStatusPracticePOJ 1797DescriptionBackgroundHugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a 阅读全文

摘要：原文：http://blog.jobbole.com/1198/代码之美，不仅在于为一个给定问题找到解决方案，而且还在代码的简单性、有效性、紧凑性和效率（内存）。代码设计比实际执行更难 。因此，每一个程序员当用C语言编程时，都应该记着这些东西。本文向你介绍规范你的C代码的10种方法。0. 避免不必要的函数调用考虑下面的2个函数：void str_print( char *str ){ int i; for ( i = 0; i < strlen ( str ); i++ ) { printf("%c",str[ i ] ); }}void str_print1 ( c 阅读全文

摘要：Silver Cow PartyTime Limit:2000MSMemory Limit:65536KB64bit IO Format:%I64d & %I64uSubmitStatusPracticePOJ 3268DescriptionOne cow from each ofNfarms (1 ≤N≤ 1000) conveniently numbered 1..Nis going to attend the big cow party to be held at farm #X(1 ≤X≤N). A total ofM(1 ≤M≤ 100,000) unidirectional 阅读全文

摘要：Xenia and Divisorstime limit per test2 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard outputXenia the mathematician has a sequence consisting ofn(nis divisible by 3) positive integers, each of them is at most 7. She wants to split the sequence into groups of three so that 阅读全文

摘要：FroggerTime Limit:1000MSMemory Limit:65536KB64bit IO Format:%I64d & %I64uSubmitStatusPracticePOJ 2253DescriptionFreddy Frog is sitting on a stone in the middle of a lake. Suddenly he notices Fiona Frog who is sitting on another stone. He plans to visit her, but since the water is dirty and full 阅读全文

摘要：Til the Cows Come HomeTime Limit:1000MSMemory Limit:65536KB64bit IO Format:%I64d & %I64uSubmitStatusPracticePOJ 2387DescriptionBessie is out in the field and wants to get back to the barn to get as much sleep as possible before Farmer John wakes her for the morning milking. Bessie needs her beau 阅读全文

摘要：转自http://aikilis.tk/如果问题中各数据的范围明确，那么无穷大的设定不是问题，在不明确的情况下，很多程序员都取0x7fffffff作为无穷大，因为这是32-bit int的最大值。如果这个无穷大只用于一般的比较（比如求最小值时min变量的初值），那么0x7fffffff确实是一个完美的选择，但是在更多的情况下，0x7fffffff并不是一个好的选择。很多时候我们并不只是单纯拿无穷大来作比较，而是会运算后再做比较，例如在大部分最短路径算法中都会使用的松弛操作：if (d[u]+w[u][v]<d[v]) d[v]=d[u]+w[u][v];我们知道如果u,v之间没有边，那么 阅读全文

摘要：例子取自：http://qt-project.org/doc/qt-4.8/stylesheet-examples.html以lineEdit为例（1）设置某个lineEdit的背景色为黄色lineEdit->setStyleSheet ("background-color:yellow");（2）设置一个应用项目中所有lineEdit的背景色均为黄色（line 4）1 int main(int argc, char *argv[])2 {3 QApplication a(argc, argv);4 a.setStyleSheet ("QLineEdit { 阅读全文