线程安全的单例模式实现有几种思路,个人认为第2种方案最优雅:
1、饿汉式
2、借助内部类
3、普通加锁解决
4、双重检测,但要注意写法
如果单体模式继续扩展为N元单体模式,那就是对象池模式了
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代码片段(4) [全屏查看所有代码]
1. [代码]饿汉式单例
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public class Singleton {
private final static Singleton INSTANCE = new Singleton();
private Singleton() { }
public static Singleton getInstance() {
return INSTANCE;
}
}
2. [代码]借助内部类
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public class Singleton {
private Singleton() { }
private static class SingletonHolder {
private final static Singleton INSTANCE = new Singleton();
}
public static Singleton getInstance() {
return SingletonHolder.INSTANCE;
}
}
属于懒汉式单例,因为Java机制规定,内部类SingletonHolder只有在getInstance()方法第一次调用的时候才会被加载(实现了lazy),而且其加载过程是线程安全的。内部类加载的时候实例化一次instance。
3. [代码]普通加锁解决
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public class Singleton {
private static Singleton instance = null;
private Singleton() { }
public static synchronized Singleton getInstance() {
if(instance == null) {
instance = new Singleton();
}
return instance;
}
}
虽然解决了线程安全问题,但是每个线程调用getInstance都要加锁,我们想要只在第一次调用getInstance时加锁,请看下面的双重检测方案
4. [代码]双重检测方案
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public class Singleton {
private static Singleton instance = null;
private Singleton() { }
public static Singleton getInstance() {
if(instance == null) {
synchronzied(Singleton.class) {
Singleton temp = instance;
if(temp == null) {
temp = new Singleton();
instance = temp
}
}
}
return instance;
}
}
由于指令重排序问题,所以不可以直接写成下面这样:
public class Singleton {
private static Singleton instance = null;
private Singleton() { }
public static Singleton getInstance() {
if(instance == null) {
synchronzied(Singleton.class) {
if(instance == null) {
instance = new Singleton();
}
}
}
return instance;
}
}
但是如果instance实例变量用volatile修饰就可以了,volatile修饰的话就可以确保instance = new Singleton();对应的指令不会重排序,如下的单例代码也是线程安全的:
public class Singleton {
private static volatile Singleton instance = null;
private Singleton() { }
public static Singleton getInstance() {
if(instance == null) {
synchronzied(Singleton.class) {
if(instance == null) {
instance = new Singleton();
}
}
}
return instance;
}
}