保证应用程序只运行一个实例[c#]

使用 互斥Mutex 保证应用程序只运行一个实例, 代码如下:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Forms;
using System.Threading;
using System.Runtime.InteropServices;

namespace TestPlatform
{
    static class Program
    {
        private static Mutex _mutex = null;
        private static string _mutexName = "ONLYONE_APP";
        private static string _titleName = "Gps设备生产测试平台";
        /// <summary>
        /// 应用程序的主入口点。
        /// </summary>
        [STAThread]
        static void Main()
        {
            // 单一实例
            try
            {
                _mutex = Mutex.OpenExisting(_mutexName);
                MessageBox.Show(_titleName + "已经运行, 请确认!", "不可重复执行", MessageBoxButtons.OK, MessageBoxIcon.Stop);

                IntPtr _handle = FindWindow(null, _titleName);
                if (_handle != IntPtr.Zero)
                {
                    //MessageBox.Show("find application.");
                    ShowWindow(_handle, SW_RESTORE);// 还原
                }
                Application.Exit();
            }
            catch (WaitHandleCannotBeOpenedException ex) // 不存在此 mutex
            {
                _mutex = new Mutex(true, _mutexName);

                Application.EnableVisualStyles();
                Application.SetCompatibleTextRenderingDefault(false);
                Application.Run(new FormMain());

                _mutex.ReleaseMutex();
            }
        }

        [DllImport("user32.dll")]
        private static extern IntPtr FindWindow(string className, string windowName);

        [DllImport("user32.dll")]
        private static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);

        private const int SW_RESTORE = 9;
    }
}

 

posted @ 2013-02-05 10:13  沧海小小粟  阅读(333)  评论(0编辑  收藏  举报