摘要: Rivest Shamir Adleman 题目给了e,n,c,n可分解,然后就是常规解rsa from gmpy2 import * from Crypto.Util.number import * p = 15485863 q = 26384008867091745294633354547835 阅读全文
posted @ 2021-03-02 00:33 寒江寻影 阅读(567) 评论(0) 推荐(0)