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2016年10月6日 #

数据库Mark.2

摘要： select count(*) as count,DATE_SUB('2016-10-04',INTERVAL regDay DAY) from result_1005 group by DATE_SUB('2016-10-04',INTERVAL regDay DAY) ORDER BY COUNT desc 阅读全文

posted @ 2016-10-06 00:08 crac 阅读(95) 评论(0) 推荐(0)