CSAPP bomblab(施工中)
规则：对于每个\(phase\)，你都需要输入一个字符串，使得\(explode\_bomb\)函数不被运行
在bomb目录下使用objdump -d bomb > bomb.s得到反汇编文件\(bomb.s\)
\(shell\) 中使用 gdb bomb进入\(gdb\)调试
phase_1
0000000000400ee0 <phase_1>:
400ee0: 48 83 ec 08 sub $0x8,%rsp
400ee4: be 00 24 40 00 mov $0x402400,%esi
400ee9: e8 4a 04 00 00 call 401338 <strings_not_equal>
400eee: 85 c0 test %eax,%eax
400ef0: 74 05 je 400ef7 <phase_1+0x17>
400ef2: e8 43 05 00 00 call 40143a <explode_bomb>
400ef7: 48 83 c4 08 add $0x8,%rsp
400efb: c3 ret
先是分配了8字节的栈空间以保存返回地址，然后进入了\(strings\_not\_equal\)函数中
0000000000401338 <strings_not_equal>:
401338: 41 54 push %r12
40133a: 55 push %rbp
40133b: 53 push %rbx
40133c: 48 89 fb mov %rdi,%rbx
40133f: 48 89 f5 mov %rsi,%rbp
401342: e8 d4 ff ff ff call 40131b <string_length>
401347: 41 89 c4 mov %eax,%r12d
40134a: 48 89 ef mov %rbp,%rdi
40134d: e8 c9 ff ff ff call 40131b <string_length>
401352: ba 01 00 00 00 mov $0x1,%edx
401357: 41 39 c4 cmp %eax,%r12d
40135a: 75 3f jne 40139b <strings_not_equal+0x63>
40135c: 0f b6 03 movzbl (%rbx),%eax
40135f: 84 c0 test %al,%al
401361: 74 25 je 401388 <strings_not_equal+0x50>
401363: 3a 45 00 cmp 0x0(%rbp),%al
401366: 74 0a je 401372 <strings_not_equal+0x3a>
401368: eb 25 jmp 40138f <strings_not_equal+0x57>
40136a: 3a 45 00 cmp 0x0(%rbp),%al
40136d: 0f 1f 00 nopl (%rax)
401370: 75 24 jne 401396 <strings_not_equal+0x5e>
401372: 48 83 c3 01 add $0x1,%rbx
401376: 48 83 c5 01 add $0x1,%rbp
40137a: 0f b6 03 movzbl (%rbx),%eax
40137d: 84 c0 test %al,%al
40137f: 75 e9 jne 40136a <strings_not_equal+0x32>
401381: ba 00 00 00 00 mov $0x0,%edx
401386: eb 13 jmp 40139b <strings_not_equal+0x63>
401388: ba 00 00 00 00 mov $0x0,%edx
40138d: eb 0c jmp 40139b <strings_not_equal+0x63>
40138f: ba 01 00 00 00 mov $0x1,%edx
401394: eb 05 jmp 40139b <strings_not_equal+0x63>
401396: ba 01 00 00 00 mov $0x1,%edx
40139b: 89 d0 mov %edx,%eax
40139d: 5b pop %rbx
40139e: 5d pop %rbp
40139f: 41 5c pop %r12
4013a1: c3 ret
阅读地址在\(401338\)的\(strings\_not\_equal\)并结合函数名推断，该函数将\(\%edi\)和\(\%esi\)指向的地址的字符串进行比较，若相等则将\(\%rax\)设为0，反之将\(\%rax\)设为1
所以这段汇编代码在\(\%edi\)和\(\%esi\)指向的字符串相同的时候不会爆炸，只需输入内存\(0x402400\)中的字符串即可
(gdb) x/s 0x402400
得到 Border relations with Canada have never been better. 即为本题答案
phase_2
0000000000400efc <phase_2>:
400efc: 55 push %rbp
400efd: 53 push %rbx
400efe: 48 83 ec 28 sub $0x28,%rsp
400f02: 48 89 e6 mov %rsp,%rsi
400f05: e8 52 05 00 00 call 40145c <read_six_numbers>
程序首先将\(\%rbp\)和\(\%rbx\)压入栈中保存状态，并为栈分配了40字节的空间，并将\(\%rsp\)栈指针放入\(\%rsi\)作为\(read\_six\_numbers\)的第二个参数
接下来我们来看\(read\_six\_numbers\)函数
000000000040145c <read_six_numbers>:
40145c: 48 83 ec 18 sub $0x18,%rsp
401460: 48 89 f2 mov %rsi,%rdx //arg 3
401463: 48 8d 4e 04 lea 0x4(%rsi),%rcx //arg 4
401467: 48 8d 46 14 lea 0x14(%rsi),%rax
40146b: 48 89 44 24 08 mov %rax,0x8(%rsp) //arg 8
401470: 48 8d 46 10 lea 0x10(%rsi),%rax
401474: 48 89 04 24 mov %rax,(%rsp) //arg 7
401478: 4c 8d 4e 0c lea 0xc(%rsi),%r9 //arg 6
40147c: 4c 8d 46 08 lea 0x8(%rsi),%r8 // arg 5
401480: be c3 25 40 00 mov $0x4025c3,%esi //arg 2
401485: b8 00 00 00 00 mov $0x0,%eax
40148a: e8 61 f7 ff ff call 400bf0 <__isoc99_sscanf@plt>
40148f: 83 f8 05 cmp $0x5,%eax
401492: 7f 05 jg 401499 <read_six_numbers+0x3d>
401494: e8 a1 ff ff ff call 40143a <explode_bomb>
401499: 48 83 c4 18 add $0x18,%rsp
40149d: c3 ret
查表发现其中部分寄存器为参数寄存器，已经在代码中标出
看到这里寄存器指向的地址有点混乱，于是我们进入gdb调试查看相关寄存器的值
通过b explode_bomb在爆炸函数前设置断点，得以保证在刚进入爆炸函数且还未爆炸之前得以停顿进而进行调试
我们随便输入一堆数，然后在断点处检查每个寄存器的值
发现
这类似C/C++中\(scanf\)的占位符，结合函数名和剩下6个参数寄存器，我们大胆推测这个函数以\(\%esi\)为占位符，读入六个\(int\)并存放在其他六个参数寄存器中，依次在\(\%rdx\)，\(\%rcx\)，\(\%r8\)，\(\%r9\)和栈中的两个位置
我们手动模拟可以得到以下结果，设最初\(\%rsp\)指向的地址为\(p\)
可以使用gdb进行验证，同时访问\((\%rax)\)的值发现是读入的数的个数
成功读入的个数传回\(\%rax\)中，当读入的个数小于等于5时炸弹会爆炸，否则函数正常退出
继续回到\(phase\_2\)中
400f0a: 83 3c 24 01 cmpl $0x1,(%rsp)
400f0e: 74 20 je 400f30 <phase_2+0x34>
400f10: e8 25 05 00 00 call 40143a <explode_bomb>
400f15: eb 19 jmp 400f30 <phase_2+0x34>
400f17: 8b 43 fc mov -0x4(%rbx),%eax
400f1a: 01 c0 add %eax,%eax
400f1c: 39 03 cmp %eax,(%rbx)
400f1e: 74 05 je 400f25 <phase_2+0x29>
400f20: e8 15 05 00 00 call 40143a <explode_bomb>
400f25: 48 83 c3 04 add $0x4,%rbx
400f29: 48 39 eb cmp %rbp,%rbx
400f2c: 75 e9 jne 400f17 <phase_2+0x1b>
400f2e: eb 0c jmp 400f3c <phase_2+0x40>
400f30: 48 8d 5c 24 04 lea 0x4(%rsp),%rbx
400f35: 48 8d 6c 24 18 lea 0x18(%rsp),%rbp
400f3a: eb db jmp 400f17 <phase_2+0x1b>
400f3c: 48 83 c4 28 add $0x28,%rsp
400f40: 5b pop %rbx
400f41: 5d pop %rbp
400f42: c3 ret
根据上图可以发现，\(\%rdx\)指向的地址即为\(\%rsp\)，即检查第一个数是否为1，若不是1则直接爆炸
此后将\(\%rbx\)设置为\(p+4\)(指向第二个数)，\(\%rbp\)设置为\(p+24\)(指向最后一个数的下一个地址)，并将执行的指令跳转到\(*0x400f17\)
将\(\%rax\)设置为\(\%rbx\)指向的前一个数，将\(p\)指向的值乘2以后与\(\%rbx\)比较，若不相等直接爆炸
此后将\(\%rbx\)指向下一个数，检查其若超出了读入的6个数地址范围则安全退出这个函数，否则重复上一行和这一行的内容
可以发现，这一段代码等价于从第二个数开始直到第六个数，检查其是否为前一个数的两倍，全部满足则能安全退出
因此只需要第一个数为1，后面的数每个都为前一个数两倍即可
故答案为 1 2 4 8 16 32
phase_3
0000000000400f43 <phase_3>:
400f43: 48 83 ec 18 sub $0x18,%rsp
400f47: 48 8d 4c 24 0c lea 0xc(%rsp),%rcx
400f4c: 48 8d 54 24 08 lea 0x8(%rsp),%rdx
400f51: be cf 25 40 00 mov $0x4025cf,%esi
400f56: b8 00 00 00 00 mov $0x0,%eax
400f5b: e8 90 fc ff ff call 400bf0 <__isoc99_sscanf@plt>
400f60: 83 f8 01 cmp $0x1,%eax
400f63: 7f 05 jg 400f6a <phase_3+0x27>
400f65: e8 d0 04 00 00 call 40143a <explode_bomb>
400f6a: 83 7c 24 08 07 cmpl $0x7,0x8(%rsp)
400f6f: 77 3c ja 400fad <phase_3+0x6a>
400f71: 8b 44 24 08 mov 0x8(%rsp),%eax
400f75: ff 24 c5 70 24 40 00 jmp *0x402470(,%rax,8)
400f7c: b8 cf 00 00 00 mov $0xcf,%eax
400f81: eb 3b jmp 400fbe <phase_3+0x7b>
400f83: b8 c3 02 00 00 mov $0x2c3,%eax
400f88: eb 34 jmp 400fbe <phase_3+0x7b>
400f8a: b8 00 01 00 00 mov $0x100,%eax
400f8f: eb 2d jmp 400fbe <phase_3+0x7b>
400f91: b8 85 01 00 00 mov $0x185,%eax
400f96: eb 26 jmp 400fbe <phase_3+0x7b>
400f98: b8 ce 00 00 00 mov $0xce,%eax
400f9d: eb 1f jmp 400fbe <phase_3+0x7b>
400f9f: b8 aa 02 00 00 mov $0x2aa,%eax
400fa4: eb 18 jmp 400fbe <phase_3+0x7b>
400fa6: b8 47 01 00 00 mov $0x147,%eax
400fab: eb 11 jmp 400fbe <phase_3+0x7b>
400fad: e8 88 04 00 00 call 40143a <explode_bomb>
400fb2: b8 00 00 00 00 mov $0x0,%eax
400fb7: eb 05 jmp 400fbe <phase_3+0x7b>
400fb9: b8 37 01 00 00 mov $0x137,%eax
400fbe: 3b 44 24 0c cmp 0xc(%rsp),%eax
400fc2: 74 05 je 400fc9 <phase_3+0x86>
400fc4: e8 71 04 00 00 call 40143a <explode_bomb>
400fc9: 48 83 c4 18 add $0x18,%rsp
400fcd: c3 ret
设最初\(\%rsp\)指向的地址是p,先是分配了24字节的栈空间,此后\(\%rsp\)，\(\%rcx\)，\(\%rdx\)，\(\%rsi\)指向的地址分别为\(p-18\),\(p-6\),\(p-10\),\(0x4025cf\),\(\%rax\)的值为0
我们使用 gdb x/s 0x4025cf发现gdb 返回的结果是 0x4025cf: "%d %d"，说明读入了两个数依次存放在\(\%rdx\)和\(\%rcx\)指向的地址中，若读入的数个数不大于1就爆炸
假设读入的两个数分别为\(x\)和\(y\)，\(x\)大于7也会爆炸
接下来将\(\%rax\)也指向地址\(p-10\)(x)，然后有一条跳转指令，注意这是一条间接跳转，会让PC地址变为 \(0x00402470 + 8 \times x\)地址中存放的值
通过 (gdb) x/16x 0x402470 我们可以得到从\(0x402470\)开始16个单位的值
一个单位为4字节32位，16个单位即为8个64位的指针，结果如下
注意\(x86-64\)下使用的是小端法
我们不妨从最后一个\(explode\_bomb\)函数开始看，想要不进入这个函数，就需要让最后\(\%rax\)的值等于\(\%rcx\)指向的值(y)
jmp *0x402470(,%rax,8)这一行后面都是对于\(\%rax\)的赋值后跳转到判断\(\%rax\)与y是否相等，所以我们只需要在输入时将y设置为对应跳转时\(\%rax\)赋的值即可
如\(x = 0\),\(\%rax=0xcf=207\)或\(x = 1\),\(\%rax = 0x137 = 311\) ...
所以本题一个可能的答案即为 0 207
phase_4
40100c <phase_4>:
40100c: 48 83 ec 18 sub $0x18,%rsp
401010: 48 8d 4c 24 0c lea 0xc(%rsp),%rcx
401015: 48 8d 54 24 08 lea 0x8(%rsp),%rdx
40101a: be cf 25 40 00 mov $0x4025cf,%esi
40101f: b8 00 00 00 00 mov $0x0,%eax
401024: e8 c7 fb ff ff call 400bf0 <__isoc99_sscanf@plt>
401029: 83 f8 02 cmp $0x2,%eax
40102c: 75 07 jne 401035 <phase_4+0x29>
40102e: 83 7c 24 08 0e cmpl $0xe,0x8(%rsp)
401033: 76 05 jbe 40103a <phase_4+0x2e>
401035: e8 00 04 00 00 call 40143a <explode_bomb>
40103a: ba 0e 00 00 00 mov $0xe,%edx
40103f: be 00 00 00 00 mov $0x0,%esi
401044: 8b 7c 24 08 mov 0x8(%rsp),%edi
401048: e8 81 ff ff ff call 400fce <func4>
40104d: 85 c0 test %eax,%eax
40104f: 75 07 jne 401058 <phase_4+0x4c>
401051: 83 7c 24 0c 00 cmpl $0x0,0xc(%rsp)
401056: 74 05 je 40105d <phase_4+0x51>
401058: e8 dd 03 00 00 call 40143a <explode_bomb>
40105d: 48 83 c4 18 add $0x18,%rsp
401061: c3 ret
同样设函数开始时\(\%rsp\)指向的地址为p,在输入前\(\%rsp\),\(\%rcx\),\(\%rdx\)指向的地址分别为\(p-24\),\(p-12\),\(p-16\)
\(0x4025cf\)中的格式为 "%d %d"，读入的个数不是2就会爆炸。设读入\(\%rdx\), \(\%rcx\)中的值分别为\(x\)和\(y\)
\(x\)大于等于14时候会发生爆炸，否则将\(\%rdx\)的值设置为14，\(\%rsi\)的值设置为0，\(\%rdi\)的值设置为\(x\)，作为参数传入\(func4\)中
根据退出\(func4\)后的代码我们知道，只有在\(\%rax=0\)且\(p-12\)这个地址的值为0的情况下才能安全退出
0000000000400fce <func4>:
400fce: 48 83 ec 08 sub $0x8,%rsp
400fd2: 89 d0 mov %edx,%eax
400fd4: 29 f0 sub %esi,%eax
400fd6: 89 c1 mov %eax,%ecx
400fd8: c1 e9 1f shr $0x1f,%ecx
400fdb: 01 c8 add %ecx,%eax
400fdd: d1 f8 sar $1,%eax
400fdf: 8d 0c 30 lea (%rax,%rsi,1),%ecx
400fe2: 39 f9 cmp %edi,%ecx
400fe4: 7e 0c jle 400ff2 <func4+0x24>
400fe6: 8d 51 ff lea -0x1(%rcx),%edx
400fe9: e8 e0 ff ff ff call 400fce <func4>
400fee: 01 c0 add %eax,%eax
400ff0: eb 15 jmp 401007 <func4+0x39>
400ff2: b8 00 00 00 00 mov $0x0,%eax
400ff7: 39 f9 cmp %edi,%ecx
400ff9: 7d 0c jge 401007 <func4+0x39>
400ffb: 8d 71 01 lea 0x1(%rcx),%esi
400ffe: e8 cb ff ff ff call 400fce <func4>
401003: 8d 44 00 01 lea 0x1(%rax,%rax,1),%eax
401007: 48 83 c4 08 add $0x8,%rsp
40100b: c3 ret
接下来是这个递归函数\(func4\)，我太菜了看不懂它叽里咕噜在说写什么，直接运用\(OI\)知识人肉反编译打表(
#include <bits/stdc++.h>
int rdi, rsi, rdx, rcx, rax;
void f() {
rax = rdx;
rax -= rsi;
rcx = rax;
rcx >>= 31;
rax += rcx;
rax >>= 1;
rcx = rax + rsi;
if (rcx <= rdi) goto x400ff2;
rdx = rcx - 1;
f();
rax += rax;
goto x401007;
x400ff2:
rax = 0;
if (rcx >= rdi) goto x401007;
rsi = rcx + 1;
f();
rax = rax + rax + 1;
x401007:
return;
}
int main() {
for (int x = 0; x <= 3; x++) {
for (int y = 0; y <= 3; y++) {
rdi = x; rsi = 0; rdx = 14; rcx = y;
f();
std::cout << "x=" << x << " y=" << y << " rax=" << rax << '\n';
}
}
}
结果如下
x=0 y=0 rax=0
x=0 y=1 rax=0
x=0 y=2 rax=0
x=0 y=3 rax=0
x=1 y=0 rax=0
x=1 y=1 rax=0
x=1 y=2 rax=0
x=1 y=3 rax=0
x=2 y=0 rax=4
x=2 y=1 rax=4
x=2 y=2 rax=4
x=2 y=3 rax=4
x=3 y=0 rax=0
x=3 y=1 rax=0
x=3 y=2 rax=0
x=3 y=3 rax=0
可知\(x\)取小于14的任意值，\(y\)取0即可满足条件
如取 0 0 即可
phase_5
0000000000401062 <phase_5>:
401062: 53 push %rbx
401063: 48 83 ec 20 sub $0x20,%rsp
401067: 48 89 fb mov %rdi,%rbx
40106a: 64 48 8b 04 25 28 00 mov %fs:0x28,%rax
401071: 00 00
401073: 48 89 44 24 18 mov %rax,0x18(%rsp)
401078: 31 c0 xor %eax,%eax
40107a: e8 9c 02 00 00 call 40131b <string_length>
40107f: 83 f8 06 cmp $0x6,%eax
401082: 74 4e je 4010d2 <phase_5+0x70>
401084: e8 b1 03 00 00 call 40143a <explode_bomb>
401089: eb 47 jmp 4010d2 <phase_5+0x70>
40108b: 0f b6 0c 03 movzbl (%rbx,%rax,1),%ecx
40108f: 88 0c 24 mov %cl,(%rsp)
401092: 48 8b 14 24 mov (%rsp),%rdx
401096: 83 e2 0f and $0xf,%edx
401099: 0f b6 92 b0 24 40 00 movzbl 0x4024b0(%rdx),%edx
4010a0: 88 54 04 10 mov %dl,0x10(%rsp,%rax,1)
4010a4: 48 83 c0 01 add $0x1,%rax
4010a8: 48 83 f8 06 cmp $0x6,%rax
4010ac: 75 dd jne 40108b <phase_5+0x29>
4010ae: c6 44 24 16 00 movb $0x0,0x16(%rsp)
4010b3: be 5e 24 40 00 mov $0x40245e,%esi
4010b8: 48 8d 7c 24 10 lea 0x10(%rsp),%rdi
4010bd: e8 76 02 00 00 call 401338 <strings_not_equal>
4010c2: 85 c0 test %eax,%eax
4010c4: 74 13 je 4010d9 <phase_5+0x77>
4010c6: e8 6f 03 00 00 call 40143a <explode_bomb>
4010cb: 0f 1f 44 00 00 nopl 0x0(%rax,%rax,1)
4010d0: eb 07 jmp 4010d9 <phase_5+0x77>
4010d2: b8 00 00 00 00 mov $0x0,%eax
4010d7: eb b2 jmp 40108b <phase_5+0x29>
4010d9: 48 8b 44 24 18 mov 0x18(%rsp),%rax
4010de: 64 48 33 04 25 28 00 xor %fs:0x28,%rax
4010e5: 00 00
4010e7: 74 05 je 4010ee <phase_5+0x8c>
4010e9: e8 42 fa ff ff call 400b30 <__stack_chk_fail@plt>
4010ee: 48 83 c4 20 add $0x20,%rsp
4010f2: 5b pop %rbx
4010f3: c3 ret
可以发现读入的是一个字符串，在其长度不为6的时候爆炸
否则将\(\%rax\)设置为0，\(\%rbx\)指向读入字符串的首地址，通过movzbl (%rbx,%rax,1),%ecx访问字符串的第一个字符，将其\(and\)上15，即取其ASCII码的后四位得到一个整数\(k\)，以movzbl 0x4024b0(%rdx),%edx访问0x4024b0的后面第\(k\)个字符并将其最终放入0x10(%rsp,%rax,1)中，重复以上流程六次，然后将地址为\(0x40245e\)的字符串放入\(\%esi\)中,\(\%rdi\)指向\(0x10(\%rsp)\)即转换后的字符串，将这两个字符串进行比较，若不相等则不会爆炸
通过 (gdb) x/s 0x4024b0，我们得到这个地址后面的字符串为 maduiersnfotvbylSo you think you can stop the bomb with ctrl-c, do you?
P.S 如果你用 (gdb) x/s 0x4024b0 结果会是一个彩蛋
"maduiersnfotvbylSo you think you can stop the bomb with ctrl-c, do you?" 0x4024f8: "Curses, you've found the secret phase!" 0x40251f: "" 0x402520: "But finding it and solving it are quite different..."
通过 (gdb) x/s 0x40245e可以得到目标字符串为 0x40245e: "flyers"
所以我们只需要输入的每个字符的\(ASCII\)码二进制后4位转换为十进制分别为9,15,14,5,6,7 就行了
查\(ASCII\)表发现 Y_.UFG为一组可能的解
phase_6
00000000004010f4 <phase_6>:
4010f4: 41 56 push %r14
4010f6: 41 55 push %r13
4010f8: 41 54 push %r12
4010fa: 55 push %rbp
4010fb: 53 push %rbx
4010fc: 48 83 ec 50 sub $0x50,%rsp
401100: 49 89 e5 mov %rsp,%r13
401103: 48 89 e6 mov %rsp,%rsi
401106: e8 51 03 00 00 call 40145c <read_six_numbers>
40110b: 49 89 e6 mov %rsp,%r14
40110e: 41 bc 00 00 00 00 mov $0x0,%r12d
401114: 4c 89 ed mov %r13,%rbp
401117: 41 8b 45 00 mov 0x0(%r13),%eax
40111b: 83 e8 01 sub $0x1,%eax
40111e: 83 f8 05 cmp $0x5,%eax
401121: 76 05 jbe 401128 <phase_6+0x34>
401123: e8 12 03 00 00 call 40143a <explode_bomb>
401128: 41 83 c4 01 add $0x1,%r12d
40112c: 41 83 fc 06 cmp $0x6,%r12d
401130: 74 21 je 401153 <phase_6+0x5f>
401132: 44 89 e3 mov %r12d,%ebx
401135: 48 63 c3 movslq %ebx,%rax
401138: 8b 04 84 mov (%rsp,%rax,4),%eax
40113b: 39 45 00 cmp %eax,0x0(%rbp)
40113e: 75 05 jne 401145 <phase_6+0x51>
401140: e8 f5 02 00 00 call 40143a <explode_bomb>
401145: 83 c3 01 add $0x1,%ebx
401148: 83 fb 05 cmp $0x5,%ebx
40114b: 7e e8 jle 401135 <phase_6+0x41>
40114d: 49 83 c5 04 add $0x4,%r13
401151: eb c1 jmp 401114 <phase_6+0x20>
401153: 48 8d 74 24 18 lea 0x18(%rsp),%rsi
401158: 4c 89 f0 mov %r14,%rax
40115b: b9 07 00 00 00 mov $0x7,%ecx
401160: 89 ca mov %ecx,%edx
401162: 2b 10 sub (%rax),%edx
401164: 89 10 mov %edx,(%rax)
401166: 48 83 c0 04 add $0x4,%rax
40116a: 48 39 f0 cmp %rsi,%rax
40116d: 75 f1 jne 401160 <phase_6+0x6c>
40116f: be 00 00 00 00 mov $0x0,%esi
401174: eb 21 jmp 401197 <phase_6+0xa3>
401176: 48 8b 52 08 mov 0x8(%rdx),%rdx
40117a: 83 c0 01 add $0x1,%eax
40117d: 39 c8 cmp %ecx,%eax
40117f: 75 f5 jne 401176 <phase_6+0x82>
401181: eb 05 jmp 401188 <phase_6+0x94>
401183: ba d0 32 60 00 mov $0x6032d0,%edx
401188: 48 89 54 74 20 mov %rdx,0x20(%rsp,%rsi,2)
40118d: 48 83 c6 04 add $0x4,%rsi
401191: 48 83 fe 18 cmp $0x18,%rsi
401195: 74 14 je 4011ab <phase_6+0xb7>
401197: 8b 0c 34 mov (%rsp,%rsi,1),%ecx
40119a: 83 f9 01 cmp $0x1,%ecx
40119d: 7e e4 jle 401183 <phase_6+0x8f>
40119f: b8 01 00 00 00 mov $0x1,%eax
4011a4: ba d0 32 60 00 mov $0x6032d0,%edx
4011a9: eb cb jmp 401176 <phase_6+0x82>
4011ab: 48 8b 5c 24 20 mov 0x20(%rsp),%rbx
4011b0: 48 8d 44 24 28 lea 0x28(%rsp),%rax
4011b5: 48 8d 74 24 50 lea 0x50(%rsp),%rsi
4011ba: 48 89 d9 mov %rbx,%rcx
4011bd: 48 8b 10 mov (%rax),%rdx
4011c0: 48 89 51 08 mov %rdx,0x8(%rcx)
4011c4: 48 83 c0 08 add $0x8,%rax
4011c8: 48 39 f0 cmp %rsi,%rax
4011cb: 74 05 je 4011d2 <phase_6+0xde>
4011cd: 48 89 d1 mov %rdx,%rcx
4011d0: eb eb jmp 4011bd <phase_6+0xc9>
4011d2: 48 c7 42 08 00 00 00 movq $0x0,0x8(%rdx)
4011d9: 00
4011da: bd 05 00 00 00 mov $0x5,%ebp
4011df: 48 8b 43 08 mov 0x8(%rbx),%rax
4011e3: 8b 00 mov (%rax),%eax
4011e5: 39 03 cmp %eax,(%rbx)
4011e7: 7d 05 jge 4011ee <phase_6+0xfa>
4011e9: e8 4c 02 00 00 call 40143a <explode_bomb>
4011ee: 48 8b 5b 08 mov 0x8(%rbx),%rbx
4011f2: 83 ed 01 sub $0x1,%ebp
4011f5: 75 e8 jne 4011df <phase_6+0xeb>
4011f7: 48 83 c4 50 add $0x50,%rsp
4011fb: 5b pop %rbx
4011fc: 5d pop %rbp
4011fd: 41 5c pop %r12
4011ff: 41 5d pop %r13
401201: 41 5e pop %r14
401203: c3 ret
secret_phase
0000000000401204 <fun7>:
401204: 48 83 ec 08 sub $0x8,%rsp
401208: 48 85 ff test %rdi,%rdi
40120b: 74 2b je 401238 <fun7+0x34>
40120d: 8b 17 mov (%rdi),%edx
40120f: 39 f2 cmp %esi,%edx
401211: 7e 0d jle 401220 <fun7+0x1c>
401213: 48 8b 7f 08 mov 0x8(%rdi),%rdi
401217: e8 e8 ff ff ff call 401204 <fun7>
40121c: 01 c0 add %eax,%eax
40121e: eb 1d jmp 40123d <fun7+0x39>
401220: b8 00 00 00 00 mov $0x0,%eax
401225: 39 f2 cmp %esi,%edx
401227: 74 14 je 40123d <fun7+0x39>
401229: 48 8b 7f 10 mov 0x10(%rdi),%rdi
40122d: e8 d2 ff ff ff call 401204 <fun7>
401232: 8d 44 00 01 lea 0x1(%rax,%rax,1),%eax
401236: eb 05 jmp 40123d <fun7+0x39>
401238: b8 ff ff ff ff mov $0xffffffff,%eax
40123d: 48 83 c4 08 add $0x8,%rsp
401241: c3 ret
0000000000401242 <secret_phase>:
401242: 53 push %rbx
401243: e8 56 02 00 00 call 40149e <read_line>
401248: ba 0a 00 00 00 mov $0xa,%edx
40124d: be 00 00 00 00 mov $0x0,%esi
401252: 48 89 c7 mov %rax,%rdi
401255: e8 76 f9 ff ff call 400bd0 <strtol@plt>
40125a: 48 89 c3 mov %rax,%rbx
40125d: 8d 40 ff lea -0x1(%rax),%eax
401260: 3d e8 03 00 00 cmp $0x3e8,%eax
401265: 76 05 jbe 40126c <secret_phase+0x2a>
401267: e8 ce 01 00 00 call 40143a <explode_bomb>
40126c: 89 de mov %ebx,%esi
40126e: bf f0 30 60 00 mov $0x6030f0,%edi
401273: e8 8c ff ff ff call 401204 <fun7>
401278: 83 f8 02 cmp $0x2,%eax
40127b: 74 05 je 401282 <secret_phase+0x40>
40127d: e8 b8 01 00 00 call 40143a <explode_bomb>
401282: bf 38 24 40 00 mov $0x402438,%edi
401287: e8 84 f8 ff ff call 400b10 <puts@plt>
40128c: e8 33 03 00 00 call 4015c4 <phase_defused>
401291: 5b pop %rbx
401292: c3 ret
401293: 90 nop
401294: 90 nop
401295: 90 nop
401296: 90 nop
401297: 90 nop
401298: 90 nop
401299: 90 nop
40129a: 90 nop
40129b: 90 nop
40129c: 90 nop
40129d: 90 nop
40129e: 90 nop
40129f: 90 nop
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