摘要：
function ajax（url,successFul){ const xhr=new XMLHttpRequest() xhr.open("Get",url,true) xhr.onreadystatechange=function() { if(xhr.readyState 4){ if(xh 阅读全文
posted @ 2022-12-22 13:44 fvnkrenfkjkd 阅读(10) 评论(0) 推荐(0) 编辑
posted @ 2022-12-22 13:44 fvnkrenfkjkd 阅读(10) 评论(0) 推荐(0) 编辑
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