摘要: \[\begin{eqnarray*}ans&=&\sum_{i=1}^ng(i)\\&=&\sum_{i=1}^n\sum_{d|i}\mu^2(d)\\&=&\sum_{i=1}^n\sum_{d|i}\sum_{k^2|d}\mu(k)\\&=&\sum_{k=1}^n\mu(k)\sum_{ 阅读全文
posted @ 2016-10-30 00:35 Claris 阅读(1237) 评论(0) 推荐(0) 编辑