Newtonsoft.Json

https://github.com/JamesNK/Newtonsoft.Json

Json.NET is a popular high-performance JSON framework for .NET http://www.newtonsoft.com/json

Popular high-performance JSON framework for .NET

 

 

将json字符串反序列化为dynamic对象

https://stackoverflow.com/questions/4749639/deserializing-json-to-net-object-using-newtonsoft-or-linq-to-json-maybe

You can use the C# dynamic type to make things easier. This technique also makes re-factoring simpler as it does not rely on magic-strings.

JSON

The JSON string below is a simple response from an HTTP API call, and it defines two properties: Id and Name.

{"Id": 1, "Name": "biofractal"}

C#

Use JsonConvert.DeserializeObject<dynamic>() to deserialize this string into a dynamic type then simply access its properties in the usual way.

dynamic results = JsonConvert.DeserializeObject<dynamic>(json);
var id = results.Id;
var name= results.Name;

If you specify the type of the results variable as dynamic, instead of using the var keyword, then the property values will correctly deserialize, e.g. Id to an int and not a JValue (thanks to GFoley83 for the comment below).

Note: The NuGet link for the Newtonsoft assembly is http://nuget.org/packages/newtonsoft.json.

 

 
https://stackoverflow.com/questions/4535840/deserialize-json-object-into-dynamic-object-using-json-net

latest json.net version allow do this:

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);

output:

 1000
 string
 6

Documentation here: LINQ to JSON with Json.NET

 

Json反序列化包含数组的字符串

https://www.experts-exchange.com/questions/28910996/in-C-when-deserializing-Json-data-which-contain-an-array-I-only-receive-the-first-object-in-the-array-how-to-correct.html

https://stackoverflow.com/questions/26372250/accessing-items-in-an-json-net-jarray-in-c-sharp 

JObject jsonObject = JObject.Parse(requestBody);
            string header = jsonObject["header"].ToString(Formatting.None);
            string encryptValue = jsonObject["parameters"].ToString(Formatting.None);
            MessageHeader messageHeader = JsonConverter.DeSerializer<MessageHeader>(header);

 

Json反序列化到List<T>

2019-01-23 11:21:51.739+08:00 ERROR [30]: Message:Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[LISA.Custom.Chile.Entity.API.CodeStockInformationRequest]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object.
Path 'header'.
StackTrace: at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateObject(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.Deserialize(JsonReader reader, Type objectType, Boolean checkAdditionalContent)
at Newtonsoft.Json.JsonSerializer.DeserializeInternal(JsonReader reader, Type objectType)
at Newtonsoft.Json.Linq.JToken.ToObject(Type objectType, JsonSerializer jsonSerializer)
at Newtonsoft.Json.Linq.JToken.ToObject(Type objectType)
at Newtonsoft.Json.Linq.JToken.ToObject[T]()
at LISA.WebApi.Chile.Controllers.CodeStocksController.CodeStockInformation(JObject obj) in C:\Users\clu\source\repos\Edenred\LISA_6.0.0.0\LISA.CMS.Chile\LISA.WebApi.Chile\Controllers\CodeStocksController.cs:line 24
method: CodeStockInformation

{
"header": {
"SecurityHash": "92d92f54aca69a57824521f40bccf43e4fd354b15ae9ee4af5b44ac104630e65"
},
"parameters": [
{
"PartnershipIDIdentification": "Partnership1",
"IdCode": "123412318"
},
{
"PartnershipIDIdentification": "Partnership1",
"IdCode": "123412359"
}
]
}

dynamic json = obj;
                MessageHeader Emp = json.header.ToObject<MessageHeader>();
                List<CodeStockInformationRequest> parameters = json.parameters.ToObject<List<CodeStockInformationRequest>>();

解决方案

https://stackoverflow.com/questions/22557559/cannot-deserialize-the-json-array-e-g-1-2-3-into-type-because-type-requ

Your json string is wrapped within square brackets ([]), hence it is interpreted as array instead of single RetrieveMultipleResponse object. Therefore, you need to deserialize it to type collection of RetrieveMultipleResponse, for example :

var objResponse1 = 
    JsonConvert.DeserializeObject<List<RetrieveMultipleResponse>>(JsonStr);

 

//JObject obj  方法的参数
                dynamic json = obj;
                List<CodeStockInformationRequest> parameters = JsonConverter.DeSerializer<List<CodeStockInformationRequest>>(json.parameters.ToString());

 

posted @ 2016-03-17 21:41  ChuckLu  阅读(451)  评论(0编辑  收藏  举报