@Scope("prototype")创建的对象为什么会一样?

用Annotation的@Scope("prototype")实验两个对象还是相等的,用xml的scope="prototype"就不一样,代码如下:

import org.springframework.context.annotation.Scope;
import org.springframework.stereotype.Component;

import com.dao.UserDAO;
import com.model.User;

@Scope("prototype")
@Component("u")

public class UserDAOImpl implements UserDAO {

@Override
public void save(User u) {
System.out.println("a user saved");

}

}

 

public class UserServiceTest {

@Test
public void testAdd() throws Exception {


ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("beans.xml");//destroy在ApplicationContext没有要用具体的类来引用

UserService service = (UserService)ctx.getBean("userService");
UserService service2 = (UserService)ctx.getBean("userService");
System.out.println(service==service2);

service.add(new User());
ctx.destroy();

}

}

 

posted on 2014-11-01 16:55  chuansao  阅读(794)  评论(0编辑  收藏  举报