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#coding=utf-8
 
#******************************************************************************
# 下面为阴历计算所需的数据,为节省存储空间,所以采用下面比较变态的存储方法.
#******************************************************************************
#数组g_lunar_month_day存入阴历1901年到2050年每年中的月天数信息,
#阴历每月只能是29或30天,一年用12(或13)个二进制位表示,对应位为1表30天,否则为29天
g_lunar_month_day = [
    0x4ae0, 0xa570, 0x5268, 0xd260, 0xd950, 0x6aa8, 0x56a0, 0x9ad0, 0x4ae8, 0x4ae0,   #1910
    0xa4d8, 0xa4d0, 0xd250, 0xd548, 0xb550, 0x56a0, 0x96d0, 0x95b0, 0x49b8, 0x49b0,   #1920
    0xa4b0, 0xb258, 0x6a50, 0x6d40, 0xada8, 0x2b60, 0x9570, 0x4978, 0x4970, 0x64b0,   #1930
    0xd4a0, 0xea50, 0x6d48, 0x5ad0, 0x2b60, 0x9370, 0x92e0, 0xc968, 0xc950, 0xd4a0,   #1940
    0xda50, 0xb550, 0x56a0, 0xaad8, 0x25d0, 0x92d0, 0xc958, 0xa950, 0xb4a8, 0x6ca0,   #1950
    0xb550, 0x55a8, 0x4da0, 0xa5b0, 0x52b8, 0x52b0, 0xa950, 0xe950, 0x6aa0, 0xad50,   #1960
    0xab50, 0x4b60, 0xa570, 0xa570, 0x5260, 0xe930, 0xd950, 0x5aa8, 0x56a0, 0x96d0,   #1970
    0x4ae8, 0x4ad0, 0xa4d0, 0xd268, 0xd250, 0xd528, 0xb540, 0xb6a0, 0x96d0, 0x95b0,   #1980
    0x49b0, 0xa4b8, 0xa4b0, 0xb258, 0x6a50, 0x6d40, 0xada0, 0xab60, 0x9370, 0x4978,   #1990
    0x4970, 0x64b0, 0x6a50, 0xea50, 0x6b28, 0x5ac0, 0xab60, 0x9368, 0x92e0, 0xc960,   #2000
    0xd4a8, 0xd4a0, 0xda50, 0x5aa8, 0x56a0, 0xaad8, 0x25d0, 0x92d0, 0xc958, 0xa950,   #2010
    0xb4a0, 0xb550, 0xb550, 0x55a8, 0x4ba0, 0xa5b0, 0x52b8, 0x52b0, 0xa930, 0x74a8,   #2020
    0x6aa0, 0xad50, 0x4da8, 0x4b60, 0x9570, 0xa4e0, 0xd260, 0xe930, 0xd530, 0x5aa0,   #2030
    0x6b50, 0x96d0, 0x4ae8, 0x4ad0, 0xa4d0, 0xd258, 0xd250, 0xd520, 0xdaa0, 0xb5a0,   #2040
    0x56d0, 0x4ad8, 0x49b0, 0xa4b8, 0xa4b0, 0xaa50, 0xb528, 0x6d20, 0xada0, 0x55b0,   #2050
]
 
#数组gLanarMonth存放阴历1901年到2050年闰月的月份,如没有则为0,每字节存两年
g_lunar_month = [
    0x00, 0x50, 0x04, 0x00, 0x20,   #1910
    0x60, 0x05, 0x00, 0x20, 0x70,   #1920
    0x05, 0x00, 0x40, 0x02, 0x06,   #1930
    0x00, 0x50, 0x03, 0x07, 0x00,   #1940
    0x60, 0x04, 0x00, 0x20, 0x70,   #1950
    0x05, 0x00, 0x30, 0x80, 0x06,   #1960
    0x00, 0x40, 0x03, 0x07, 0x00,   #1970
    0x50, 0x04, 0x08, 0x00, 0x60,   #1980
    0x04, 0x0a, 0x00, 0x60, 0x05,   #1990
    0x00, 0x30, 0x80, 0x05, 0x00,   #2000
    0x40, 0x02, 0x07, 0x00, 0x50,   #2010
    0x04, 0x09, 0x00, 0x60, 0x04,   #2020
    0x00, 0x20, 0x60, 0x05, 0x00,   #2030
    0x30, 0xb0, 0x06, 0x00, 0x50,   #2040
    0x02, 0x07, 0x00, 0x50, 0x03    #2050
]
 
#==================================================================================
 
from datetime import date, datetime
from calendar import Calendar as Cal
 
START_YEAR = 1901
 
def is_leap_year(tm):
    y = tm.year
    return (not (y % 4)) and (y % 100) or (not (y % 400))
 
def show_month(tm):
    (ly, lm, ld) = get_ludar_date(tm)
    print
    print u"%d年%d月%d日" % (tm.year, tm.month, tm.day), week_str(tm), 
    print u"\t农历:", y_lunar(ly), m_lunar(lm), d_lunar(ld)
    print
    print u"日\t一\t二\t三\t四\t五\t六"
 
    c = Cal()
    ds = [d for d in c.itermonthdays(tm.year, tm.month)]
    count = 0
    for d in ds:
        print_str = ''
        if count == 0 and 0 in ds:
            print_str += '\t'
        count += 1
        if d == 0:
            print print_str+"\t",
            continue
 
        (ly, lm, ld) = get_ludar_date(datetime(tm.year, tm.month, d))
        if count % 7 == 0:
            print
 
        d_str = str(d)
        if d == tm.day:
            d_str = u"*" + d_str
        print d_str + d_lunar(ld) + u"\t",
    print
 
def this_month():
    show_month(datetime.now())
 
#www.iplaypython.com
 
def week_str(tm):
    a = u'星期一 星期二 星期三 星期四 星期五 星期六 星期日'.split()
    return a[tm.weekday()]
 
def d_lunar(ld):
    a = u'初一 初二 初三 初四 初五 初六 初七 初八 初九 初十\
         十一 十二 十三 十四 十五 十六 十七 十八 十九 廿十\
         廿一 廿二 廿三 廿四 廿五 廿六 廿七 廿八 廿九 三十'.split()
    return a[ld - 1]
 
def m_lunar(lm):
    a = u'正月 二月 三月 四月 五月 六月 七月 八月 九月 十月 十一月 十二月'.split()
    return a[lm - 1]
 
def y_lunar(ly):
    y = ly
    tg = u'甲 乙 丙 丁 戊 己 庚 辛 壬 癸'.split()
    dz = u'子 丑 寅 卯 辰 巳 午 未 申 酉 戌 亥'.split()
    sx = u'鼠 牛 虎 免 龙 蛇 马 羊 猴 鸡 狗 猪'.split()
    return tg[(y - 4) % 10] + dz[(y - 4) % 12] + u' ' + sx[(y - 4) % 12] + u''
 
def date_diff(tm):
    return (tm - datetime(1901, 1, 1)).days
 
def get_leap_month(lunar_year):
    flag = g_lunar_month[(lunar_year - START_YEAR) / 2]
    if (lunar_year - START_YEAR) % 2:
        return flag & 0x0f
    else:
        return flag >> 4
 
def lunar_month_days(lunar_year, lunar_month):
    if (lunar_year < START_YEAR):
        return 30
 
    high, low = 0, 29
    iBit = 16 - lunar_month;
 
    if (lunar_month > get_leap_month(lunar_year) and get_leap_month(lunar_year)):
        iBit -= 1
 
    if (g_lunar_month_day[lunar_year - START_YEAR] & (1 << iBit)):
        low += 1
         
    if (lunar_month == get_leap_month(lunar_year)):
        if (g_lunar_month_day[lunar_year - START_YEAR] & (1 << (iBit -1))):
             high = 30
        else:
             high = 29
 
    return (high, low)
 
def lunar_year_days(year):
    days = 0
    for i in range(1, 13):
        (high, low) = lunar_month_days(year, i)
        days += high
        days += low
    return days
 
def get_ludar_date(tm):
    span_days = date_diff(tm)
 
    #阳历1901年2月19日为阴历1901年正月初一
    #阳历1901年1月1日到2月19日共有49天
    if (span_days <49):
        year = START_YEAR - 1
        if (span_days <19):
          month = 11;  
          day = 11 + span_days
        else:
            month = 12;
            day = span_days - 18
        return (year, month, day)
 
    #下面从阴历1901年正月初一算起
    span_days -= 49
    year, month, day = START_YEAR, 1, 1
    #计算年
    tmp = lunar_year_days(year)
    while span_days >= tmp:
        span_days -= tmp
        year += 1
        tmp = lunar_year_days(year)
 
    #计算月
    (foo, tmp) = lunar_month_days(year, month)
    while span_days >= tmp:
        span_days -= tmp
        if (month == get_leap_month(year)):
            (tmp, foo) = lunar_month_days(year, month)
            if (span_days < tmp):
                return (0, 0, 0)
            span_days -= tmp
        month += 1
        (foo, tmp) = lunar_month_days(year, month)
 
    #计算日
    day += span_days
    return (year, month, day)
 
#功能简单,只打印当月的
this_month()
posted on 2016-07-25 17:29  Chen Jian  阅读(4790)  评论(0编辑  收藏  举报