674. Longest Continuous Increasing Subsequence@python

Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

题目地址: Longest Continuous Increasing Subsequence

难度: Easy

题意: 找出呈递增的趋势的子数组,返回最大长度

思路:

遍历数组,并计数,比较简单

class Solution(object):
def findLengthOfLCIS(self, nums): """ :type nums: List[int] :rtype: int """ n = len(nums) if n <= 1: return len(nums) res = 0 length = 1 for i in range(n-1): if nums[i] < nums[i+1]: length += 1 else: res = max(length, res) length = 1 res = max(length, res) return res

时间复杂度: O(n)

空间复杂度: O(1)

 

posted @ 2018-09-30 18:10  静静地挖坑  阅读(130)  评论(0)    收藏  举报