摘要: select id ,json_extract_scalar(json_item,'$.user_id') as user_id ,json_extract_scalar(json_item,'$.url') as user_id from ( select A.id ,concat('{',rep 阅读全文
posted @ 2022-07-23 20:11 chenzechao 阅读(1418) 评论(0) 推荐(0)