2019年8月28日
mysql查同个实例两个数据库中的表名差异
摘要： select TABLE_NAME from ( select TABLE_NAME ,count(1) as cnt from information_schema.tables where TABLE_SCHEMA in ('db_a','db_b') and (table_name not like '%2018%' and table_name not like '%2019%') gro 阅读全文
posted @ 2019-08-28 14:30 chenzechao 阅读(613) 评论(0) 推荐(0)