摘要:
t = (double)getTickCount(); Mat img1(1000, 1000, CV_32F); for (int i=0; i(i,j) = 3.2f; } } t = (double)getTickCount() - t; printf("in %gms\n", t*1000/getTickFrequency()); //*************************************************************** t = (double)getTickCount();... 阅读全文
posted @ 2013-07-11 23:26
chchche
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