摘要:
Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).The replacement must be in-place, do not allocate extra memory.He 阅读全文
posted @ 2014-03-20 19:44
xchangcheng
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摘要:
The set[1,2,3,…,n]contains a total ofn! unique permutations.By listing and labeling all of the permutations in order,We get the following sequence (ie, forn= 3):"123""132""213""231""312""321"Givennandk, return thekthpermutation sequence.Not 阅读全文
posted @ 2014-03-20 16:49
xchangcheng
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摘要:
Given a collection of numbers that might contain duplicates, return all possible unique permutations.For example,[1,1,2]have the following unique permutations:[1,1,2],[1,2,1], and[2,1,1].Solution:由于数据中有重复,在递归时需要判断是否可以交换。基本的枚举思路是每个数分别出现在第k位,然后排列剩下的元素。这里第k位的元素在枚举过程中需要判断是否已经出现过。class Solution {public: 阅读全文
posted @ 2014-03-20 11:00
xchangcheng
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