摘要: - let xhr = new XMLHttpRequest() - xhr.onreadystatechange=function(){ if(xhr.readystate 4&&xhr.status 200){ console.log(xhr.response) } } - xhr.open(请 阅读全文
posted @ 2021-11-24 11:20 七友の 阅读(20) 评论(0) 推荐(0)