摘要:
画一个列表自己试试,二分法 # The isBadVersion API is already defined for you. # @param version, an integer # @return an integer # def isBadVersion(version): class 阅读全文
posted @ 2021-06-06 16:26
泊鸽
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摘要:
看似简单,实际上想了挺久的 1)内置api方法 class Solution: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None: """ Do not return anything, modif 阅读全文
posted @ 2021-06-06 15:58
泊鸽
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