摘要:
leetcode 626 換座位 SELECT (CASE WHEN MOD(id, 2) != 0 AND counts != id THEN id + 1 WHEN MOD(id, 2) != 0 AND counts = id THEN id ELSE id - 1 END) AS id, s 阅读全文
posted @ 2023-05-09 17:57
Carl_ZhangJH
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摘要:
leetcode 619 只出現一次的最大數字 select max(num) as num from ( select num as num from MyNumbers group by num having count(num) = 1 ) as mn select if(count(num) 阅读全文
posted @ 2023-05-09 17:57
Carl_ZhangJH
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