摘要: 分数排名 select s1.score, count(distinct s2.score) as `rank` from Scores as s1, Scores as s2 where s1.score <= s2.score group by s1.id order by s1.score d 阅读全文
posted @ 2023-04-10 17:55 Carl_ZhangJH 阅读(21) 评论(0) 推荐(0)
摘要: 第N高的薪水 CREATE FUNCTION getNthHighestSalary(N INT) RETURNS INT BEGIN declare T int default 0; SET T = N-1; RETURN ( # Write your MySQL query statement 阅读全文
posted @ 2023-04-10 17:00 Carl_ZhangJH 阅读(12) 评论(0) 推荐(0)