实验五

任务1

#include <stdio.h>
#include <string.h> 
#define N 3        
typedef struct student {
    int id;             
    char name[20];          
    char subject[20];    
    double perf;         
    double mid;         
    double final;         
    double total;         
    char level[10];     
} STU;

void input(STU[], int);            
void output(STU[], int);            
void calc(STU[], int);                
int fail(STU[], STU[], int);        
void sort(STU[], int);                

int main() {
    STU st[N], fst[N];   
    int k;  

    printf("录入学生成绩信息:\n");
    input(st, N);

    printf("\n成绩处理...\n");
    calc(st, N);

    k = fail(st, fst, N);
    sort(st, N);
    printf("\n学生成绩排名情况:\n");
    output(st, N);

    printf("\n不及格学生信息:\n");
    output(fst, k);

    return 0;
}

void input(STU s[], int n) {
    int i;

    for (i = 0; i < n; i++)
        scanf_s("%d %s %s %lf %lf %lf", &s[i].id, s[i].name,8, s[i].subject,10,
            &s[i].perf, &s[i].mid, &s[i].final);
}

void output(STU s[], int n) {
    int i;

    printf("-----------------\n");
    printf("学号   姓名     科目   平时   期中   期末   总评   等级\n");
    for (i = 0; i < n; i++)
        printf("%d   %-6s   %-4s   %-4.0f   %-4.0f   %-4.0f   %-4.1f   %s\n", s[i].id, s[i].name, s[i].subject, s[i].perf, s[i].mid, s[i].final, s[i].total, s[i].level);
}


void calc(STU s[], int n) {
    int i;

    for (i = 0; i < n; i++) {
        s[i].total = s[i].perf * 0.2 +
            s[i].mid * 0.2 +
            s[i].final * 0.6;

        if (s[i].total >= 90)
            strcpy_s(s[i].level, "");
        else if (s[i].total >= 80 && s[i].total < 90)
            strcpy_s(s[i].level, "");
        else if (s[i].total >= 70 && s[i].total < 80)
            strcpy_s(s[i].level, "");
        else if (s[i].total >= 60 && s[i].total < 70)
            strcpy_s(s[i].level, "及格");
        else
            strcpy_s(s[i].level, "不及格");
    }
}

int fail(STU s[], STU t[], int n) {
    int i, k = 0;

    for (i = 0; i < n; i++)
        if (s[i].total < 60)
            t[k++] = s[i];

    return k;
}


void sort(STU s[], int n) {
    int i, j;
    STU t;

    for (i = 0; i < n - 1; i++)
        for (j = 0; j < n - 1 - i; j++)
            if (s[j].total < s[j + 1].total) {
                t = s[j];
                s[j] = s[j + 1];
                s[j + 1] = t;
            }
}

 

 任务2

#include <stdio.h>
#include <string.h>
#define N 10
#define M 80

typedef struct {
    char name[M];       
    char author[M];     
} Book;

int main() {
    Book x[N] = { {"《一九八四》", "乔治.奥威尔"},
                  {"《美丽新世界》", "赫胥黎"},
                  {"《昨日的世界》", "斯蒂芬.茨威格"},
                  {"《万历十五年》", "黄仁宇"},
                  {"《一只特立独行的猪》", "王小波"},
                  {"《百年孤独》", "马尔克斯"},
                  {"《情人》", "玛格丽特.杜拉斯"},
                  {"《只是孩子》", "帕蒂.史密斯"},
                  {"《刀锋》", "毛姆"},
                  {"《沉默的大多数》", "王小波"} };
    Book* ptr;
    int i;
    char author[M];
    printf("所有图书信息: \n");
    for (ptr = x; ptr < x + N; ++ptr)
        printf("%-30s%-30s\n", ptr->name, ptr->author);
    printf("\n输入作者名: ");
    gets_s(author);
    for (ptr = x; ptr < x + N; ++ptr)
        if (strcmp(ptr->author, author) == 0) {
            printf("%-30s%-30s\n", ptr->name, ptr->author);
        }

    return 0;
}

 

 任务3

#include <stdio.h>
#include<string.h>
#define  N 100

typedef  struct {
    char num[10];       
    int s1;             
    int s2;             
    double sum;         
    char level[10];     
} STU;


int fun(STU a[], int n, STU h[]); 

int main() {
    STU s[N] = { {"GA05", 85, 76},
               {"GA03", 76, 90},
               {"GA02", 69, 90},
               {"GA04", 85, 56},
               {"GA01", 91, 95},
               {"GA07", 72, 80},
               {"GA08", 64, 45},
               {"GA06", 87, 98},
               {"GA015", 85, 86},
               {"GA013", 91, 97} };      
    STU h[N];                        
    int i, k, n = 10;
    k = fun(s, n, h);
    printf("There are :\n");
    for (i = 0; i < k; i++)
        printf("%s %d %d %.2f %s\n", h[i].num, h[i].s1, h[i].s2, h[i].sum, h[i].level);

    return 0;
}

int fun(STU a[], int n, STU h[]) {
    int i,j=0;
    for (i = 0; i <= n - 1; i++)
    {
        a[i].sum = a[i].s1 * 0.7 + a[i].s2 * 0.3;
    }
    double ave_sum, s=0;
    for(i=0;i<=n-1;i++)
    {
        s = s + a[i].sum;
    }
    ave_sum = s / n;
    for (i = 0; i <= n - 1; i++)
    {
        if (a[i].sum > ave_sum)
        {
            strcpy_s(h[j].num, a[i].num);
            h[j].s1 = a[i].s1;
            h[j].s2 = a[i].s2;
            h[j].sum = a[i].sum;
            strcpy_s(h[j].level, "均分以上");
            j++;
        }
    }
    return j;
}

 

 任务4

#include <stdio.h>
#include <string.h>
#define N 5

typedef struct student {
    char name[10];
    int num;
    int maths;
    int computer;
    int english;
    int sum;
    char level[10];
} STU;
void fun(STU a[], int n);
int main() {
    STU s[6 * N] = { {"A001", 1, 34, 67, 80},
                 {"B003", 3, 78, 87, 90},
                 {"A002", 2, 90, 98, 99},
                 {"B002", 4, 56, 78, 98},
                 {"A005", 5, 35, 67, 79} };
    int i;
    fun(s, N);
    for (i = 0; i < N; i++)
        printf("%s %d %d %d %d %d %s\n", s[i].name, s[i].num, s[i].maths, s[i].computer, s[i].english, s[i].sum, s[i].level);
    return 0;
}
void fun(STU a[], int n) {
    int i;
    int min, max;

    for (i = 0; i < n; i++)
    {
        a[i].sum = a[i].maths + a[i].computer + a[i].english;
    }
    min = a[0].sum;
    max = a[0].sum;
    for (i = 0; i < n; i++)
    {
        if (a[i].sum < min)
            min = a[i].sum;
    }
    for (i = 0; i < n; i++)
    {
        if (a[i].sum > max)
            max = a[i].sum;
    }

    for (i = 0; i < n; i++)
    {
        if (a[i].sum == min)
            strcpy_s(a[i].level, "不及格");
        else if (a[i].sum == max)
            strcpy_s(a[i].level, "优秀");
        else
            strcpy_s(a[i].level, "合格");
    }
}

 

 任务5

#include <stdio.h>
#include<string.h>
#define N 5

typedef struct student {
    long no;
    char name[20];
    int score;
} STU;
void input(STU s[], int n);
int find_min_list(STU s[], STU t[], int n);
void output(STU s[], int n);

int main() {
    STU stu[N], min_list[N];
    int count;

    printf("录入%d个学生信息\n", N);
    input(stu, N);

    printf("\n统计最低分人数和学生信息...\n");
    count = find_min_list(stu, min_list, N);

    printf("\n一共有%d个最低分,信息如下:\n", count);
    output(min_list, count);

    return 0;
}
void input(STU s[], int n) {
    int i;
    for (i = 0; i <= n - 1; i++)
    {
        scanf_s("%ld %s %d", &s[i].no, s[i].name,5, &s[i].score);
    }
}
void output(STU s[], int n) {
    int i;
    for (i = 0; i <= n - 1; i++)
    {
        printf("%ld %s %d\n", s[i].no, s[i].name,s[i].score);
    }
}
int find_min_list(STU s[], STU t[], int n) {
    int i, j=0, min = s[0].score;
    for (i = 1; i <= n - 1; i++)
    {
        if (s[i].score < min)
            min = s[i].score;
    }
    for (i = 0; i <= n - 1; i++)
    {
        if (s[i].score == min)
        {
            t[j].no = s[i].no;
            strcpy_s(t[j].name, s[i].name);
            t[j].score = min;
            j++;
        }
    }
    return j;
}

 

posted @ 2022-12-27 22:10  疙瘩宝  阅读(18)  评论(0编辑  收藏  举报