摘要: 一年OI一场空,原题game见祖宗 阅读全文
posted @ 2018-11-12 09:57 Splitor 阅读(551) 评论(0) 推荐(0) 编辑
摘要: 天下本无不散之宴席,纵使风和雨,无悔入OI。 阅读全文
posted @ 2018-11-12 08:57 Splitor 阅读(332) 评论(0) 推荐(3) 编辑
摘要: 1.Time and frequency characterization of signals and systems sd sd sd 阅读全文
posted @ 2021-12-13 16:04 Splitor 阅读(37) 评论(0) 推荐(0) 编辑
该文被密码保护。 阅读全文
posted @ 2020-02-27 16:43 Splitor 阅读(0) 评论(0) 推荐(0) 编辑
该文被密码保护。 阅读全文
posted @ 2020-02-08 12:55 Splitor 阅读(10) 评论(0) 推荐(0) 编辑
摘要: 模拟 用栈维护 注意: 1、就算有语法错误也要将读入都读完。 2、注意防止RE 3、每一层的复杂度要取max code: include include include include include include include include include include define in 阅读全文
posted @ 2018-11-09 10:18 Splitor 阅读(435) 评论(0) 推荐(0) 编辑
摘要: 憨题,除了要写高精度,分行考虑,直接区间dp 60pts: include include include include include include include include using namespace std; define maxn 106 define int long lon 阅读全文
posted @ 2018-11-08 16:54 Splitor 阅读(221) 评论(0) 推荐(0) 编辑
摘要: 水题 19:46开始看题,20:09AC 就是大力dp啊,设dp[i][j]表示考虑到第i个点,距离它为j的数量,第一次倒推,求出子树中的,第二次正推,从父节点转移 转移见代码 阅读全文
posted @ 2018-11-07 20:14 Splitor 阅读(138) 评论(0) 推荐(0) 编辑
摘要: 区间do 大力设状态,设dp[i][j][0/1]代表左右端点位i,j的区间,最后加入的是左端点还是右端点。转移: // luogu judger enable o2 include include include include include include include include in 阅读全文
posted @ 2018-11-07 12:29 Splitor 阅读(126) 评论(0) 推荐(0) 编辑
摘要: 大力dp 首先设出状态:dp[i][j][k][0/1]代表了匹配到了a串的第i位,b串的第j位,已经选出了k次,这一位是否必须选,然后转移见代码吧qwq: 空间可能吃不消,用滚动数组优化第一位 include include include include include include incl 阅读全文
posted @ 2018-11-07 12:23 Splitor 阅读(151) 评论(0) 推荐(0) 编辑