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What is the sum of the digits of the number 21000 public static int sumDigits(int n) { int int_retVal = 0; int int_pow = (int) Math.pow(2, n); String 阅读全文
posted @ 2020-06-24 17:23
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LocalDateTime <=> String //时间转字符串格式化 DateTimeFormatter df1 = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS"); String dateTime = LocalDateTime.n 阅读全文
posted @ 2020-06-24 17:20
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已知 a^2+b^2=c^2(a,b,c 为自然数,a<b<c),且a+b+c=1000,求abc的值? public static int getABC() { int resVal = 1; for (int a = 0; a <= 1000; a++) { for (int b = 1; b 阅读全文
posted @ 2020-06-24 14:47
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