python 合并k个有序链表
from heapq import heappush, heappop
class Solution:
def mergeKLists(self, lists):
q = []
for i,head in enumerate(lists):
if head:
heappush(q, (head.val, i, head))
node = dummy = ListNode(0)
while q:
val, i, pop_node = heappop(q)
print(val)
node.next = ListNode(val)
node = node.next
next_node = pop_node.next
if next_node:
heappush(q, (next_node.val, i, next_node))
return dummy.next
为啥有i???????????理由见后、
另外PQ也有这个问题
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
import queue
class Solution:
def mergeKLists(self, lists: List[ListNode]) -> ListNode:
q = queue.PriorityQueue()
for i,head in enumerate(lists):
if head:
q.put((head.val, i, head))
node = dummy = ListNode(0)
while not q.empty():
val, i, pop_node = q.get()
node.next = ListNode(val)
node = node.next
next_node = pop_node.next
if next_node:
q.put((next_node.val, i, next_node))
return dummy.next
python 3 heappush Line 13: TypeError: '<' not supported between instances of 'ListNode' and 'ListNode'
出现原因:
Last Edit: October 11, 2018 9:42 PM
Read More
Python3 env will get TypeError: '<' not supported between instances of 'ListNode' and 'ListNode'
if there are duplicate values in the list. Works in Python env.

浙公网安备 33010602011771号
@cbmbbz In the event that two or more of the lists have the same
val, this code will error out since thequeuemodule will compare the second element in the priority queue which is aListNodeobject (and this is not a comparable type).To solve for this issue, I have stored
(node.val, list_idx, node)to account for this edge case.from queue import PriorityQueue # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def mergeKLists(self, lists): k = len(lists) q = PriorityQueue(maxsize=k) dummy = ListNode(None) curr = dummy for list_idx, node in enumerate(lists): if node: q.put((node.val, list_idx, node)) while q.qsize() > 0: poped = q.get() curr.next, list_idx = poped[2], poped[1] curr = curr.next if curr.next: q.put((curr.next.val, list_idx, curr.next)) return dummy.next