摘要: linux 下shell加法操作总结:#!/bin/bashn=1;echo -n "$n "let "n = $n + 1"echo -n "$n ": $((n = $n + 1))echo -n "$n "(( n = n +1 ))echo -n "$n ": $[ n = $n +1 ]echo -n "$n "n=$[ $n + 1 ]echo -n "$n "let "n++"echo -n "$n " 阅读全文
posted @ 2013-09-17 10:40 蒋蒋 阅读(8946) 评论(0) 推荐(0) 编辑