杭电ACM--2503a/b+c/d

a/b + c/d

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4200    Accepted Submission(s): 2457

Problem Description
给你2个分数,求他们的和,并要求和为最简形式。
 
Input
输入首先包含一个正整数T(T<=1000),表示有T组测试数据,然后是T行数据,每行包含四个正整数a,b,c,d(0<a,b,c,d<1000),表示两个分数a/b 和 c/d。
 
Output
对于每组测试数据,输出两个整数e和f,表示a/b + c/d的最简化结果是e/f,每组输出占一行。
 
Sample Input
2
1 2 1 3
4 3 2 3
 
Sample Output
5 6
2 1

 

 1 import java.util.Scanner;
2
3 public class Main {
4 public static int MaxCommonDivisor(int m,int n){
5 int temp;
6 if(m<n){
7 temp = m;
8 m = n;
9 n = temp;
10 }
11 while(n!=0){
12 temp = m%n;
13 m = n;
14 n = temp;
15 }
16 return m;
17 }
18 public static void main(String[] args) {
19 Scanner scan = new Scanner(System.in);
20 int t = scan.nextInt();
21 int a,b,c,d,e,f;
22 for(int i=1;i<=t;i++){
23 a = scan.nextInt();
24 b = scan.nextInt();
25 c = scan.nextInt();
26 d = scan.nextInt();
27 e = a*d+b*c;
28 f = b*d;
29 int gcd = MaxCommonDivisor(e,f);
30 e = e/gcd;
31 f = f/gcd;
32 System.out.println(e+" "+f);
33 }
34 }
35 }

 

posted @ 2012-04-03 10:33  编程小神仙  阅读(259)  评论(0编辑  收藏  举报