python找出列表重复值

a = ['l', 'i', 'u', 'h', 'a', 'i', 'w', 'e', 'n']
print [val for val in list(set(a)) if a.count(val)==2]
[root@iZ94h14przhZ ~]# python python_list.py
['i']





转载自:https://www.2cto.com/kf/201512/452758.html

posted @ 2017-12-06 09:22  banlucainiao  阅读(69)  评论(0)    收藏  举报