python找出列表重复值
a = ['l', 'i', 'u', 'h', 'a', 'i', 'w', 'e', 'n']
print [val for val in list(set(a)) if a.count(val)==2]
[root@iZ94h14przhZ ~]# python python_list.py
['i']
a = ['l', 'i', 'u', 'h', 'a', 'i', 'w', 'e', 'n']
print [val for val in list(set(a)) if a.count(val)==2]
[root@iZ94h14przhZ ~]# python python_list.py
['i']