hdu 1150 Machine Schedule hdu 1151 Air Raid 匈牙利模版

//两道大水……哦不 两道结论题

结论：二部图的最小覆盖数=二部图的最大匹配数

有向图的最小覆盖数=节点数-二部图的最大匹配数

 1 //hdu 1150
 2 #include<cstdio>
 3 #include<iostream>
 4 #include<cmath>
 5 #include<algorithm>
 6 #include<cstring>
 7 #include<cstdlib>
 8 #include<queue>
 9 #include<vector>
10 #include<map>
11 #include<stack>
12 #include<string>
13 
14 using namespace std;
15 
16 int n,m,k;
17 int f[101][101];
18 int link[101];
19 bool adj[101];
20 bool used[101];
21 
22 bool work(int x){
23     for (int i=1;i<m;i++){
24             if (f[x][i] && adj[i]==false){
25                     adj[i]=true;
26                     if (!used[i] || work(link[i])){
27                             link[i]=x;
28                             used[i]=1;
29                             //printf("%d %d\n",x,i);
30                             return true;
31                     }
32             }
33     }
34     return false;
35 }
36 
37 int main(){
38     while (scanf("%d%d%d",&n,&m,&k)==3){
39             memset(f,0,sizeof(f));
40             memset(used,0,sizeof(used));
41             for (int i=0;i<k;i++){
42                     int x,y,z;
43                     scanf("%d%d%d",&z,&x,&y);
44                     if (x!=0 && y!=0){
45                             f[x][y]=1;
46                     }
47             }
48             int ans=0;
49             for (int i=1;i<n;i++){
50                     memset(adj,0,sizeof(adj));
51                     if (work(i)) ans++;
52             }
53             //for (int i=1;i<m;i++) printf("%d %d\n",i,link[i]);
54             printf("%d\n",ans);
55     }
56     return 0;
57 }
58 /*
59 5 5 10
60 0 1 1
61 1 1 2
62 2 1 3
63 3 1 4
64 4 2 1
65 5 2 2
66 6 2 3
67 7 2 4
68 8 3 3
69 9 4 3
70 5 5 10
71 0 1 1
72 1 1 2
73 2 1 3
74 3 1 4
75 4 2 1
76 5 2 2
77 6 2 3
78 7 2 4
79 8 3 3
80 9 4 3
81 0
82 */
View Code
 1 //hdu 1151
 2 #include<cstdio>
 3 #include<iostream>
 4 #include<cmath>
 5 #include<algorithm>
 6 #include<cstring>
 7 #include<cstdlib>
 8 #include<queue>
 9 #include<vector>
10 #include<map>
11 #include<stack>
12 #include<string>
13 
14 using namespace std;
15 
16 int T;
17 int n,m;
18 bool f[121][121];
19 int link[121];
20 bool adj[121];
21 bool used[121];
22 
23 bool work(int x){
24     for (int i=1;i<=n;i++){
25             if (f[x][i] && !adj[i]){
26                     adj[i]=1;
27                     if (!used[i] || work(i)){
28                             link[i]=x;
29                             used[i]=1;
30                             return true;
31                     }
32             }
33     }
34     return false;
35 }
36 
37 int main(){
38     scanf("%d",&T);
39     for (int cas=1;cas<=T;cas++){
40             memset(used,0,sizeof(used));
41             memset(link,0,sizeof(link));
42             memset(f,0,sizeof(f));
43             scanf("%d",&n);
44             scanf("%d",&m);
45             for (int i=0;i<m;i++){
46                     int x,y;
47                     scanf("%d%d",&x,&y);
48                     f[x][y]=1;
49             }
50             int ans=n;
51             for (int i=1;i<=n;i++){
52                     memset(adj,0,sizeof(adj));
53                     if (work(i)) ans--;
54             }
55             printf("%d\n",ans);
56     }
57     return 0;
58 }
59 /*
60 2
61 4
62 3
63 3 4
64 1 3
65 2 3
66 3
67 3
68 1 3
69 1 2
70 2 3
71 */
View Code

 

posted @ 2015-07-17 15:06  鼠宝宝  阅读(176)  评论(0)  编辑  收藏  举报