【神奇の做法】bzoj2456 mode

题解：http://www.tuicool.com/articles/BfQBzif

#include<cstdio>
using namespace std;
int n,x,ans,tot;
int main()
{
    scanf("%d",&n);
    for(;n>0;n--)
      {
          scanf("%d",&x);
          if(!tot) {ans=x; tot=1;}
          else if(x==ans) tot++;
          else tot--;
      }
    printf("%d\n",ans);
    return 0;
}