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摘要： 按题意模拟下打出前几项可以看得出是肥波纳妾数列模拟代码：View Code #include <stdio.h>int sum;int b[45];int n;void solve(int d){ if(d > n) { sum++; return ; } b[d] = 0; solve(d+1); if(b[d-1]==0) { b[d] = 1; solve(d+1); }}int main(void){ sum = 0; int t; scanf("%d",&t); ... 阅读全文