摘要: task4 点击查看代码 #include<stdio.h> int main(){ FILE *fp; int sum=0; char ch; fp=fopen("data4.txt","r"); if(fp==NULL){ printf("不能打开文件\n"); return 1; } ch=f 阅读全文
posted @ 2024-06-18 17:32 乄北 阅读(25) 评论(0) 推荐(0)