摘要: LightOJ1027 A Dangerous Maze 思路:简单概率。 #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int maxn = 105; int gcd(int x, 阅读全文
posted @ 2021-08-07 09:23 Nanachi 阅读(53) 评论(0) 推荐(0)