摘要: 刘汝佳新书题题意求是求不在任意一个简单奇圈的点的个数先求双连通分量,再用二分图判断是否是奇圈View Code #include <iostream>#include <cstdio>#include <cstring>#include <vector>#include <stack>using namespace std;#define MAXN 1005int A[MAXN][MAXN];int n,m;struct Edge{ int u,v;};vector<int>G[MAXN],bcc[MAXN];int pr 阅读全文
posted @ 2013-01-10 00:08 z.arbitrary 阅读(318) 评论(0) 推荐(1)