mysql数据库题目练习

 

正文

表名和字段

–1.学生表 
Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 
–2.课程表 
Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 
–3.教师表 
Teacher(t_id,t_name) –教师编号,教师姓名 
–4.成绩表 
Score(s_id,c_id,s_score) –学生编号,课程编号,分数

测试数据

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#–1.学生表 
#Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别
CREATE TABLE `Student` (
    `s_id` VARCHAR(20),
    s_name VARCHAR(20) NOT NULL DEFAULT '',
    s_brith VARCHAR(20) NOT NULL DEFAULT '',
    s_sex VARCHAR(10) NOT NULL DEFAULT '',
    PRIMARY KEY(s_id)
);

#–2.课程表 
#Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 
create table Course(
    c_id varchar(20),
    c_name VARCHAR(20) not null DEFAULT '',
    t_id VARCHAR(20) NOT NULL,
    PRIMARY KEY(c_id)
);

/*
–3.教师表 
Teacher(t_id,t_name) –教师编号,教师姓名 
*/
CREATE TABLE Teacher(
    t_id VARCHAR(20),
    t_name VARCHAR(20) NOT NULL DEFAULT '',
    PRIMARY KEY(t_id)
);

/*
–4.成绩表 
Score(s_id,c_id,s_score) –学生编号,课程编号,分数
*/
Create table Score(
    s_id VARCHAR(20),
    c_id VARCHAR(20) not null default '',
    s_score INT(3),
    primary key(`s_id`,`c_id`)
);
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插入数据

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#--插入学生表测试数据
#('01' , '赵雷' , '1990-01-01' , '男')
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
insert into Student values('08' , '王菊' , '1990-01-20' , '女');

#--课程表测试数据
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');

#--教师表测试数据
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');

#--成绩表测试数据
insert into Score values('01' , '01' , 80);
insert into Score values('01' , '02' , 90);
insert into Score values('01' , '03' , 99);
insert into Score values('02' , '01' , 70);
insert into Score values('02' , '02' , 60);
insert into Score values('02' , '03' , 80);
insert into Score values('03' , '01' , 80);
insert into Score values('03' , '02' , 80);
insert into Score values('03' , '03' , 80);
insert into Score values('04' , '01' , 50);
insert into Score values('04' , '02' , 30);
insert into Score values('04' , '03' , 20);
insert into Score values('05' , '01' , 76);
insert into Score values('05' , '02' , 87);
insert into Score values('06' , '01' , 31);
insert into Score values('06' , '03' , 34);
insert into Score values('07' , '02' , 89);
insert into Score values('07' , '03' , 98);

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练习题和sql语句

1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

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-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
select a.*,b.s_score as score01,c.s_score as score02 FROM
  student a
  JOIN score b ON a.s_id=b.s_id and b.c_id='01'
  LEFT JOIN score c on a.s_id=c.s_id and c.c_id='02' or c.c_id = NULL
WHERE b.s_score>c.s_score ;

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2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

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-- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
 
select a.* ,b.s_score as 01_score,c.s_score as 02_score from 
    student a left join score b on a.s_id=b.s_id and b.c_id='01' or b.c_id=NULL 
     join score c on a.s_id=c.s_id and c.c_id='02' where b.s_score<c.s_score
 
 
-- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 
    student b 
    join score a on b.s_id = a.s_id
    GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)>=60;
 
 
-- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
        -- (包括有成绩的和无成绩的)
 
select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 
    student b 
    left join score a on b.s_id = a.s_id
    GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)<60
    union
select a.s_id,a.s_name,0 as avg_score from 
    student a 
    where a.s_id not in (
                select distinct s_id from score);
 
 
-- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
select a.s_id,a.s_name,count(b.c_id) as sum_course,sum(b.s_score) as sum_score from 
    student a 
    left join score b on a.s_id=b.s_id
    GROUP BY a.s_id,a.s_name;
 
 
-- 6、查询"李"姓老师的数量 
select count(t_id) from teacher where t_name like '李%';
 
-- 7、查询学过"张三"老师授课的同学的信息 
select a.* from 
    student a 
    join score b on a.s_id=b.s_id where b.c_id in(
        select c_id from course where t_id =(
            select t_id from teacher where t_name = '张三'));
 
-- 8、查询没学过"张三"老师授课的同学的信息 
select * from 
    student c 
    where c.s_id not in(
        select a.s_id from student a join score b on a.s_id=b.s_id where b.c_id in(
            select c_id from course where t_id =(
                select t_id from teacher where t_name = '张三')));
-- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
 
select a.* from 
    student a,score b,score c 
    where a.s_id = b.s_id  and a.s_id = c.s_id and b.c_id='01' and c.c_id='02';
 
-- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
 
select a.* from 
    student a 
    where a.s_id in (select s_id from score where c_id='01' ) and a.s_id not in(select s_id from score where c_id='02')
-- 11、查询没有学全所有课程的同学的信息 
select s.* from 
    student s where s.s_id in(
        select s_id from score where s_id not in(
            select a.s_id from score a 
                join score b on a.s_id = b.s_id and b.c_id='02'
                join score c on a.s_id = c.s_id and c.c_id='03'
            where a.c_id='01'))
-- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 
select * from student where s_id in(
    select distinct a.s_id from score a where a.c_id in(select a.c_id from score a where a.s_id='01')
    );
 
-- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 
 
select a.* from student a where a.s_id in(
    select distinct s_id from score where s_id!='01' and c_id in(select c_id from score where s_id='01')
    group by s_id 
    having count(1)=(select count(1) from score where s_id='01'));
-- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名 
select a.s_name from student a where a.s_id not in (
    select s_id from score where c_id = 
                (select c_id from course where t_id =(
                    select t_id from teacher where t_name = '张三')) 
                group by s_id);
 
-- 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 
select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from 
    student a 
    left join score b on a.s_id = b.s_id
    where a.s_id in(
            select s_id from score where s_score<60 GROUP BY  s_id having count(1)>=2)
    GROUP BY a.s_id,a.s_name
 
-- 16、检索"01"课程分数小于60,按分数降序排列的学生信息
select a.*,b.c_id,b.s_score from 
    student a,score b 
    where a.s_id = b.s_id and b.c_id='01' and b.s_score<60 ORDER BY b.s_score DESC;
 
-- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
select a.s_id,(select s_score from score where s_id=a.s_id and c_id='01') as 语文,
                (select s_score from score where s_id=a.s_id and c_id='02') as 数学,
                (select s_score from score where s_id=a.s_id and c_id='03') as 英语,
            round(avg(s_score),2) as 平均分 from score a  GROUP BY a.s_id ORDER BY 平均分 DESC;
 
-- 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
--及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
select a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),
    ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,
    ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,
    ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优良率,
    ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优秀率
    from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name
-- 19、按各科成绩进行排序,并显示排名(实现不完全)
-- mysql没有rank函数
    select a.s_id,a.c_id,
        @i:=@i +1 as i保留排名,
        @k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,
        @score:=a.s_score as score
    from (
        select s_id,c_id,s_score from score WHERE c_id='01' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
    union
    select a.s_id,a.c_id,
        @i:=@i +1 as i,
        @k:=(case when @score=a.s_score then @k else @i end) as rank,
        @score:=a.s_score as score
    from (
        select s_id,c_id,s_score from score WHERE c_id='02' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
    union
    select a.s_id,a.c_id,
        @i:=@i +1 as i,
        @k:=(case when @score=a.s_score then @k else @i end) as rank,
        @score:=a.s_score as score
    from (
        select s_id,c_id,s_score from score WHERE c_id='03' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
-- 20、查询学生的总成绩并进行排名
select a.s_id,
    @i:=@i+1 as i,
    @k:=(case when @score=a.sum_score then @k else @i end) as rank,
    @score:=a.sum_score as score
from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,
    (select @k:=0,@i:=0,@score:=0)s
-- 21、查询不同老师所教不同课程平均分从高到低显示 
    select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a
        left join score b on a.c_id=b.c_id 
        left join teacher c on a.t_id=c.t_id
        GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;
-- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
 
            select d.*,c.排名,c.s_score,c.c_id from (
                select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id='01'    
            )c
            left join student d on c.s_id=d.s_id
            where 排名 BETWEEN 2 AND 3
            UNION
            select d.*,c.排名,c.s_score,c.c_id from (
                select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id='02'    
            )c
            left join student d on c.s_id=d.s_id
            where 排名 BETWEEN 2 AND 3
            UNION
            select d.*,c.排名,c.s_score,c.c_id from (
                select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id='03'    
            )c
            left join student d on c.s_id=d.s_id
            where 排名 BETWEEN 2 AND 3;
 
 
-- 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比
 
 
        select distinct f.c_name,a.c_id,b.`85-100`,b.百分比,c.`70-85`,c.百分比,d.`60-70`,d.百分比,e.`0-60`,e.百分比 from score a
                left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as `85-100`,
                                            ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count(*)),2) as 百分比
                                from score GROUP BY c_id)b on a.c_id=b.c_id
                left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as `70-85`,
                                            ROUND(100*(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count(*)),2) as 百分比
                                from score GROUP BY c_id)c on a.c_id=c.c_id
                left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as `60-70`,
                                            ROUND(100*(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count(*)),2) as 百分比
                                from score GROUP BY c_id)d on a.c_id=d.c_id
                left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as `0-60`,
                                            ROUND(100*(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比
                                from score GROUP BY c_id)e on a.c_id=e.c_id
                left join course f on a.c_id = f.c_id
-- 24、查询学生平均成绩及其名次 
        select a.s_id,
                @i:=@i+1 as '不保留空缺排名',
                @k:=(case when @avg_score=a.avg_s then @k else @i end) as '保留空缺排名',
                @avg_score:=avg_s as '平均分'
        from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id)a,(select @avg_score:=0,@i:=0,@k:=0)b;
-- 25、查询各科成绩前三名的记录
            -- 1.选出b表比a表成绩大的所有组
            -- 2.选出比当前id成绩大的 小于三个的
        select a.s_id,a.c_id,a.s_score from score a 
            left join score b on a.c_id = b.c_id and a.s_score<b.s_score
            group by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3
            ORDER BY a.c_id,a.s_score DESC
 
-- 26、查询每门课程被选修的学生数 
 
        select c_id,count(s_id) from score a GROUP BY c_id
 
-- 27、查询出只有两门课程的全部学生的学号和姓名 
        select s_id,s_name from student where s_id in(
                select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);
 
-- 28、查询男生、女生人数 
        select s_sex,COUNT(s_sex) as 人数  from student GROUP BY s_sex
 
-- 29、查询名字中含有"风"字的学生信息
 
        select * from student where s_name like '%风%';
 
-- 30、查询同名同性学生名单,并统计同名人数 
 
        select a.s_name,a.s_sex,count(*) from student a  JOIN 
                    student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex
        GROUP BY a.s_name,a.s_sex
 
 
 
-- 31、查询1990年出生的学生名单
 
        select s_name from student where s_birth like '1990%'
 
-- 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 
 
    select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC
 
-- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 
 
    select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a
        left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85
 
-- 34、查询课程名称为"数学",且分数低于60的学生姓名和分数 
 
        select a.s_name,b.s_score from score b LEFT JOIN student a on a.s_id=b.s_id where b.c_id=(
                    select c_id from course where c_name ='数学') and b.s_score<60
 
-- 35、查询所有学生的课程及分数情况; 
 
 
        select a.s_id,a.s_name,
                    SUM(case c.c_name when '语文' then b.s_score else 0 end) as '语文',
                    SUM(case c.c_name when '数学' then b.s_score else 0 end) as '数学',
                    SUM(case c.c_name when '英语' then b.s_score else 0 end) as '英语',
                    SUM(b.s_score) as  '总分'
        from student a left join score b on a.s_id = b.s_id 
        left join course c on b.c_id = c.c_id 
        GROUP BY a.s_id,a.s_name
 
 
 -- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 
            select a.s_name,b.c_name,c.s_score from course b left join score c on b.c_id = c.c_id
                left join student a on a.s_id=c.s_id where c.s_score>=70
 
 
 
-- 37、查询不及格的课程
        select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course b on a.c_id = b.c_id
            where a.s_score<60 
 
--38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; 
        select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id
            where a.c_id = '01' and a.s_score>80
 
-- 39、求每门课程的学生人数 
        select count(*) from score GROUP BY c_id;
 
-- 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
 
 
        -- 查询老师id   
        select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三'
        -- 查询最高分(可能有相同分数)
        select MAX(s_score) from score where c_id='02'
        -- 查询信息
        select a.*,b.s_score,b.c_id,c.c_name from student a
            LEFT JOIN score b on a.s_id = b.s_id
            LEFT JOIN course c on b.c_id=c.c_id
            where b.c_id =(select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三')
            and b.s_score in (select MAX(s_score) from score where c_id='02')
-- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 
    select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score
-- 42、查询每门功成绩最好的前两名 
        -- 牛逼的写法
    select a.s_id,a.c_id,a.s_score from score a
        where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id
-- 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列  
        select c_id,count(*) as total from score GROUP BY c_id HAVING total>5 ORDER BY total,c_id ASC
-- 44、检索至少选修两门课程的学生学号 
        select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2
-- 45、查询选修了全部课程的学生信息 
        select * from student where s_id in(        
            select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))
--46、查询各学生的年龄
    -- 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
    select s_birth,(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y') - 
                (case when DATE_FORMAT(NOW(),'%m%d')>DATE_FORMAT(s_birth,'%m%d') then 0 else 1 end)) as age
        from student;
 
 
-- 47、查询本周过生日的学生
    select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))=WEEK(s_birth)
    select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
 
    select WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
 
-- 48、查询下周过生日的学生
    select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =WEEK(s_birth)
 
-- 49、查询本月过生日的学生
 
    select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d')) =MONTH(s_birth)
 
-- 50、查询下月过生日的学生
    select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =MONTH(s_birth)
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正文

表结构

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DROP DATABASE IF EXISTS test1;
CREATE DATABASE test1;
USE test1;
##部门表
#DROP IF EXISTS TABLE DEPT;
CREATE TABLE DEPT(
DEPTNO int PRIMARY KEY,##部门编号
DNAME VARCHAR(14) , ##部门名称
LOC VARCHAR(13) ##部门地址
) ;
INSERT INTO DEPT VALUES (10,'ACCOUNTING','NEW YORK');
INSERT INTO DEPT VALUES (20,'RESEARCH','DALLAS');
INSERT INTO DEPT VALUES (30,'SALES','CHICAGO');
INSERT INTO DEPT VALUES (40,'OPERATIONS','BOSTON');
##员工表
#DROP IF EXISTS TABLE EMP;
CREATE TABLE EMP(
EMPNO int PRIMARY KEY, #员工编号
ENAME VARCHAR(10), #员工姓名
JOB VARCHAR(9), #员工工作
MGR int, #员工直属领导编号
HIREDATE DATE, #入职时间
SAL double, #工资
COMM double, #奖金
DEPTNO int #对应dept表的外键
);
## 添加 部门 和 员工 之间的主外键关系
ALTER TABLE EMP ADD CONSTRAINT FOREIGN KEY EMP(DEPTNO) REFERENCES DEPT (DEPTNO);
INSERT INTO EMP VALUES(7369,'SMITH','CLERK',7902,"1980-12-17",800,NULL,20);
INSERT INTO EMP VALUES(7499,'ALLEN','SALESMAN',7698,'1981-02-20',1600,300,30);
INSERT INTO EMP VALUES(7521,'WARD','SALESMAN',7698,'1981-02-22',1250,500,30);
INSERT INTO EMP VALUES(7566,'JONES','MANAGER',7839,'1981-04-02',2975,NULL,20);
INSERT INTO EMP VALUES(7654,'MARTIN','SALESMAN',7698,'1981-09-28',1250,1400,30);
INSERT INTO EMP VALUES(7698,'BLAKE','MANAGER',7839,'1981-05-01',2850,NULL,30);
INSERT INTO EMP VALUES(7782,'CLARK','MANAGER',7839,'1981-06-09',2450,NULL,10);
INSERT INTO EMP VALUES(7788,'SCOTT','ANALYST',7566,'1987-07-03',3000,NULL,20);
INSERT INTO EMP VALUES(7839,'KING','PRESIDENT',NULL,'1981-11-17',5000,NULL,10);
INSERT INTO EMP VALUES(7844,'TURNER','SALESMAN',7698,'1981-09-08',1500,0,30);
INSERT INTO EMP VALUES(7876,'ADAMS','CLERK',7788,'1987-07-13',1100,NULL,20);
INSERT INTO EMP VALUES(7900,'JAMES','CLERK',7698,'1981-12-03',950,NULL,30);
INSERT INTO EMP VALUES(7902,'FORD','ANALYST',7566,'1981-12-03',3000,NULL,20);
INSERT INTO EMP VALUES(7934,'MILLER','CLERK',7782,'1981-01-23',1300,NULL,10);
#工资等级表
#DROP IF EXISTS TABLE SALGRADE;
CREATE TABLE SALGRADE(
GRADE int, #等级
LOSAL double, #最低工资
HISAL double ); #最高工资
INSERT INTO SALGRADE VALUES (1,700,1200);
INSERT INTO SALGRADE VALUES (2,1201,1400);
INSERT INTO SALGRADE VALUES (3,1401,2000);
INSERT INTO SALGRADE VALUES (4,2001,3000);
INSERT INTO SALGRADE VALUES (5,3001,9999);
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单表查询题目及答案

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#1、查找部门30中员工的详细信息。
select * from emp where deptno = 30;
#2、找出从事clerk工作的员工的编号、姓名、部门号。
select empno,ename,deptno from emp where job = 'clerk';
#3、检索出奖金多于基本工资的员工信息。
select * from emp where comm > sal;
#4、检索出奖金多于基本工资60%的员工信息。
select * from emp where comm > sal * 0.6;
#5、找出10部门的经理、20部门的职员 的员工信息。
select * from emp where deptno = 10 and job='MANAGER' or deptno = 20 and job = 'CLERK';
#6、找出10部门的经理、20部门的职员 或者既不是经理也不是职员但是工资高于2000元的员工信息。
select * from emp
where deptno = 10 and job='MANAGER'
or deptno = 20 and job = 'CLERK'
or job!='MANAGER' and job != 'CLERK' and sal > 2000 ;
## job not in ('MANAGER','CLERK')
#7、找出获得奖金的员工的工作。
select * from emp where comm > 0;
#8、找出奖金少于100或者没有获得奖金的员工的信息。
select * from emp where comm < 100 or comm is null;
#9、找出姓名以A、B、S开始的员工信息。
select * from emp where ename like 'A%' or ename like 'B%' or ename like 'S%';
#10、找到名字长度为6个字符的员工信息。
select * from emp where length(ename) = 6;
#select * from emp where ename like '______';
#11、名字中不包含R字符的员工信息。
select * from emp where ename not like '%R%';
#12、返回员工的详细信息并按姓名排序。
select * from emp order by ename asc;
#13、返回员工的信息并按工作降序工资升序排列。
select * from emp order by job desc , sal asc;
#14、计算员工的日薪(按30天)。
select ename,sal/30 as '日薪' from emp;
select ename,truncate(sal/30,2) '日薪' from emp;
#15、找出姓名中包含A的员工信息。
select * from emp where ename like '%A%';
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多表查询题目及答案

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#1、返回拥有员工的部门名、部门号。
select distinct d.dname, d.deptno from dept d,emp e where d.deptno = e.deptno;
#2、工资水平多于smith的员工信息。
select *from emp where sal > (select sal from emp where ename = 'smith');
#3、返回员工和所属经理的姓名。
select e.ename,m.ename from emp e
left outer join emp m on e.mgr = m.empno;
select e.ename ,(select m.ename from emp m where m.empno = e.mgr) ename from emp e;
select e.ename , m.ename from emp e , emp m where e.mgr = m.empno;
#4、返回雇员的雇佣日期早于其经理雇佣日期的员工及其经理姓名。
select e.ename,m.ename from emp e
inner join emp m on e.mgr = m.empno
where e.hiredate < m.hiredate;
select e.ename,m.ename from emp e,emp m
where e.mgr=m.empno
and e.hiredate < m.hiredate;
#5、返回员工姓名及其所在的部门名称。
select e.ename,d.dname from emp e , dept d where e.deptno = d.deptno;
#6、返回从事clerk工作的员工姓名和所在部门名称。
select e.ename,d.dname
from emp e , dept d
where e.deptno = d.deptno and e.job = 'CLERK';
#7、返回部门号及其本部门的最低工资。
select deptno ,min(sal) sal
from emp
group by deptno
#8、返回销售部(sales)所有员工的姓名。
select e.ename from emp e,dept d
where e.deptno = d.deptno and d.dname = 'sales';
select ename from emp where deptno=(select deptno from dept where dname='sales');
#9、返回工资水平多于平均工资的员工。
select * from emp e
where e.sal > (select avg(sal) from emp);
#10、返回与SCOTT从事相同工作的员工。
select * from emp
where job = (select job from emp where ename = 'scott');
select e1.* from emp e1 , (select empno,job from emp where ename = 'scott') e2
where e1.job = e2.job and e1.empno != e2.empno;
#11、返回与30部门员工工资水平相同的员工姓名与工资。
select ename,sal from emp
where sal in (select sal from emp where deptno = 30);
#12、返回工资高于30部门所有员工工资水平的员工信息。
select * from emp
where sal > all(select sal from emp where deptno = 30);
select * from emp
where sal > (select max(sal) from emp where deptno = 30);
#13、返回部门号、部门名、部门所在位置及其每个部门的员工总数。
select dept.deptno,dept.dname,dept.loc,count(emp.deptno) number from dept,emp
where dept.deptno = emp.deptno
group by emp.deptno;
#14、返回员工的姓名、所在部门名及其工资。
select ename,dname,sal from emp ,dept
where emp.deptno = dept.deptno;
#15、返回员工的详细信息。(包括部门名)
select e.* , d.dname from emp e, dept d
where e.deptno = d.deptno;
#16、返回员工工作及其从事此工作的最低工资。
select job , min(sal) sal from emp
group by job
#17、计算出员工的年薪,并且以年薪排序。
select ename, sal * 12 as ySalary from emp order by ySalary;
#18、返回工资处于第四级别的员工的姓名。
select ename,sal from emp e ,salgrade s
where e.sal >= s.losal and e.sal <= s.hisal
and s.grade = 4;
select emp.ename,emp.sal from
emp ,(select losal,hisal from salgrade where grade=4) g
where emp.sal between g.losal and g.hisal;
#19、返回工资为二等级的职员名字、部门所在地、和二等级的最低工资和最高工资
select ename ,dname ,sal ,losal,hisal from emp,dept,salgrade
where emp.deptno = dept.deptno and grade = 2
and sal >= losal and sal < hisal;
#20.工资等级多于smith的员工信息。
select grade from salgrade s ,emp e
where s.losal < e.sal and s.hisal > e.sal and e.ename = 'smith';
select e.* from emp e, salgrade s
where s.hisal < e.sal and s.grade = 1;
select e.* from emp e, salgrade s
where s.hisal < e.sal and s.grade = (select grade from salgrade s ,emp e
where s.losal < e.sal and s.hisal > e.sal and e.ename = 'smith');
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posted @ 2019-10-17 19:39  AnthonyWang  阅读(293)  评论(0)    收藏  举报