257. Binary Tree Paths

Given a binary tree, return all root-to-leaf paths.

For example, given the following binary tree:

 

   1

 /   \

2     3

 \

  5

 

All root-to-leaf paths are:

["1->2->5", "1->3"]

 

Solution1: dfs, recursion. use the dfs function.

 

 1 class Solution {
 2 public:
 3     vector<string> binaryTreePaths(TreeNode* root) {
 4         vector<string> res;
 5         if (!root) return res;
 6         dfs(res,root,to_string(root->val));
 7         return res;
 8     }
 9         
10     void dfs(vector<string> res, TreeNode* root, string path){
11         if (!root->left && !root->right){
12             res.push_back(path);
13             return;
14         }
15         if (root->left) dfs(res,root->left,path+"->"+to_string(root->left->val));
16         if (root->right) dfs(res, root->right, path+"->"+to_string(root->right->val));
17     }                                                                      
18 };

 

posted @ 2017-05-11 12:44  anghostcici  阅读(92)  评论(0)  编辑  收藏  举报