Loading

摘要: UpFileContent upfile = new UpFileContent(); upfile.StationImageName = "123.png"; FileStream fs = new FileStream(@"E:\123.jpg", FileMode.Open, FileAccess.Read); Byte[] btye2 = new byte[fs.Length]; fs.Read(btye2, 0, Convert.ToInt32(fs.Length)); f... 阅读全文
posted @ 2013-12-02 09:03 androllen 阅读(863) 评论(0) 推荐(0)