2011年6月28日
lucene打分规则
摘要： 0.17677669 = (MATCH) fieldWeight(title_analyze:火锅 in 0), product of: 1.4142135 = tf(termFreq(title_analyze:火锅)=2) 1.0 = idf(docFreq=2, maxDocs=3) 0.125 = fieldNorm(field=title_analyze, doc=0)score=tf*idf*fieldNormtf=根号termFreq；如1.4142135 = tf(termFreq=2)，1 = tf(termFreq=1)idf=log(maxdoc/(docFreq+1)) 阅读全文
posted @ 2011-06-28 10:50 iaac 阅读(248) 评论(0) 推荐(0)