摘要: 方法一: a = 1 b = 1 count = 2 while True: c = a + b count += 1 if count >= 101: print(c) break a = b b = c a = 0 b = 1 count = 2 print(0) print(1) while 阅读全文
posted @ 2020-03-21 14:45 Alrenn 阅读(550) 评论(0) 推荐(0)
摘要: 方法一: print(0) print(1) a = 0 b = 1 while True: c = a + b if c > 100: break a = b b = c print(c) # 100以内的菲波那切数列 a = 0 b = 1 print(a) print(b) while Tru 阅读全文
posted @ 2020-03-21 14:43 Alrenn 阅读(1165) 评论(0) 推荐(0)