2017年7月6日
oracle 字符串排序
摘要： WITH temp0 AS (SELECT LEVEL lv FROM dual CONNECT BY LEVEL <= 100) SELECT MAX(REPLACE(sys_connect_by_path(str, ' '), ' ', '')) f1 FROM (SELECT str, row 阅读全文
posted @ 2017-07-06 17:32 albert_think 阅读(3557) 评论(0) 推荐(0)