摘要: #include<bits/stdc++.h> //求n个数的最小公倍数 #define lcm(a,b) a / gcd(a,b)*b long gcd(long m,long n) { while(n) { long tmp = m % n; m = n; n = tmp; } return m 阅读全文
posted @ 2020-09-15 21:33 Akmf's_blog 阅读(98) 评论(0) 推荐(0)