摘要:
1.xml文件格式如下:<?xml version="1.0" encoding="utf-8"?><projects><project name="PlatformFramewo" vss-path="Platform$/Source CodHdt$Pla~1.sln" /></projects> 1.读取DataSet ds = new DataSet();ds.ReadXml(Server.MapPath(@"Projects.xml")); 阅读全文
posted @ 2012-10-26 18:01
简单的执着_俊
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