摘要:
View Code #include<iostream>using namespace std;int main(){ int a[]={12,4,65,8,325,9,88,56,45,17,77}; int *p1,*p2,t,length; length=sizeof(a)/sizeof(a[0]); p1=a;p2=a+length-1; for(int i=0;i<length/2;i++){ t=*p1;*p1=*p2;*p2=t; p1++; p2--; } for(int i=0;i<lengt... 阅读全文
posted @ 2012-08-19 16:38
爱嘉牛LA
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