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递归与非递归实现斐波那契数列

 1 public class Test {
 2 
 3     // 递归实现斐波那契数列
 4     public int f(int n) {
 5         if (n == 0 || n == 1) {
 6             return 1;
 7         } else if (n > 1) {
 8             return f(n - 1) + f(n - 2);
 9         } else {
10             return 0;
11         }
12     }
13 
14     public void testF(int n) {
15         for (int i = 0; i < n; i++) {
16             System.out.print("f[" + i + "]=" + f(i) + "  ");
17         }
18     }
19 
20     // 非递归实现斐波那契数列
21     public void printF(int n) {
22         int sum = 0, sum1 = 0, sum2 = 0;
23         for (int i = 0; i < n; i++) {
24             if (i == 0 || i == 1) {
25                 sum = 1;
26                 System.out.print("f[" + i + "]=" + sum + "  ");
27                 sum1 = sum;
28                 sum2 = sum;
29             } else {
30                 sum = sum1 + sum2;
31                 System.out.print("f[" + i + "]=" + sum + "  ");
32                 sum1 = sum2;
33                 sum2 = sum;
34             }
35         }
36     }
37     
38     public static void main(String[] args) {
39         new Test().testF(10);
40         new Test().printF(10);
41     }
42 
43 }

 

posted @ 2017-05-04 15:36  贾树丙  阅读(632)  评论(0编辑  收藏  举报