# bzoj3262: 陌上花开 三维偏序cdq分治

/**************************************************************
Problem: 3262
User: walfy
Language: C++
Result: Accepted
Time:3844 ms
Memory:28640 kb
****************************************************************/

//#pragma GCC optimize("Ofast,no-stack-protector")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("unroll-loops")
#include<bits/stdc++.h>
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define pi acos(-1.0)
#define ll long long
#define vi vector<int>
#define mod 1000000007
#define ld long double
#define C 0.5772156649
#define ls l,m,rt<<1
#define rs m+1,r,rt<<1|1
#define pll pair<ll,ll>
#define pil pair<int,ll>
#define pli pair<ll,int>
#define pii pair<int,int>
#define cd complex<double>
#define ull unsigned long long
#define base 1000000000000000000
#define Max(a,  b) ((a)>(b)?(a):(b))
#define Min(a,  b) ((a)<(b)?(a):(b))
#define fio ios::sync_with_stdio(false);cin.tie(0)
inline ll gcd(ll a,ll b){return b?gcd(b,a%b):a;}
inline ll qp(ll a,ll b){ll ans=1;while(b){if(b&1)ans=ans*a%mod;a=a*a%mod,b>>=1;}return ans;}

using namespace std;

const double eps=1e-8;
const ll INF=0x3f3f3f3f3f3f3f3f;
const int N=1000000+10,maxn=50000+10,inf=0x3f3f3f3f;

struct node{
int x,y,z,w,ans;
bool operator <(const node &rhs)const{
return x<rhs.x || x==rhs.x&&y<rhs.y ||x==rhs.x&&y==rhs.y&&z<rhs.z;
}
}a[N];
inline bool cmp(node a,node b){return a.y<b.y||a.y==b.y&&a.z<b.z||a.y==b.y&&a.z==b.z&&a.x<b.x;}
struct BIT{
int sum[N];
{
for(;i<N;i+=i&(-i))sum[i]+=v;
}
int query(int i)
{
int ans=0;
for(;i;i-=i&(-i))ans+=sum[i];
return ans;
}
}b;
int num[N];
void cdq(int l,int r)
{
if(l==r){a[l].ans+=a[l].w-1;return ;}
int m=(l+r)>>1;
cdq(l,m);cdq(m+1,r);
sort(a+l,a+m+1,cmp);sort(a+m+1,a+r+1,cmp);
int now=l;
for(int i=m+1;i<=r;i++)
{
a[i].ans+=b.query(a[i].z);
}
for(int i=l;i<now;i++)
}
int main()
{
int n,k;
scanf("%d%d",&n,&k);
for(int i=1;i<=n;i++)
scanf("%d%d%d",&a[i].x,&a[i].y,&a[i].z),a[i].ans=1;
sort(a+1,a+1+n);
int cnt=0;
for(int i=1;i<=n;i++)
{
if(i!=1&&a[i].x==a[i-1].x&&a[i].y==a[i-1].y&&a[i].z==a[i-1].z)a[cnt].w++;
else a[++cnt]=a[i],a[cnt].w=1;
}
cdq(1,cnt);
sort(a+1,a+1+cnt);
for(int i=1;i<=cnt;i++)num[a[i].ans]+=a[i].w;
for(int i=1;i<=n;i++)printf("%d\n",num[i]);
return 0;
}
/********************
10 3
3 3 3
2 3 3
2 3 1
3 1 1
3 1 2
1 3 1
1 1 2
1 2 2
1 3 2
1 2 1
********************/
posted @ 2018-07-23 23:22  walfy  阅读(123)  评论(0编辑  收藏  举报